CODEWITHSUNDEEP
pythonoverflowexception
user3075021
user3075021

Reputation: 91

python OverflowError error with square operator outside of power function

I am implementing the power function and the following works. However, when I replace self.myPow(x*x,n/2) with self.myPow(x,n/2)**2, I got OverflowError: (34, 'Numerical result out of range'). I thought these two equivalent, what did I miss?

class Solution(object):
    def myPow(self, x, n):
        """
        :type x: float
        :type n: int
        :rtype: float
        """

        if n==0:
            return 1
        elif n==1:
            return x
        elif n>=1 and n%2==0:
            return self.myPow(x*x,n/2)
        elif n>=1 and n%2==1:
            return self.myPow(x*x,(n-1)/2) * x
        else:
            return 1/self.myPow(x,-n)

Upvotes: -2

Views: 16

Answers (0)

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