CODEWITHSUNDEEP
bashassemblyshellcode
c0sx86
c0sx86

Reputation: 1

Shellcode for executing "ls -la" in Bash

Currently I am trying to learn how to create shell code. Right now I have the current code with runs "ls" in Bash in Linux

global _start 

section .text 

_start: 
    mov al, 59
    xor rdx, rdx 
    push rdx 
    mov rdi, '/bin//ls' 
    push rdi 
    mov rdi, rsp 
    push rdx 
    push rdi 
    mov rsi, rsp
    syscall

Now I need to modify it to run "ls -la" (essentially adding another argument).

Edit: I've tried to to add "-la" to the data that will be moved in rdi (so "mov rdi, 'bin//ls -la'") Which does not work and results in a segmentation fault.

(Note I am using execve(char *command, char *argv[], char *envp[]) here, not any functions from libc)

From what I know, I need to pass my second argument to rsi, so I tried adding:

mov rsi, '-la'
push rsi 
xor rsi, rsi
push rsi

Although again it would end up in a segmentation fault. After that, I'm kind of stuck

Upvotes: -4

Views: 75

Answers (0)

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