CODEWITHSUNDEEP
androidaudioshare
Kartik Domadiya
Kartik Domadiya

Reputation: 29968

Get URI of .mp3 file stored in res/raw folder in android

I have many .mp3 files stored in res/raw folder.

I am getting URI of .mp3 file using following code.

Uri.parse("android.resource:///com.my.android.sharesound/"+resId);

This returns : android.resource:///com.my.android.sharesound/2130968609

Now I am using this URI in creating Share Intent

    shareIntent.putExtra(Intent.EXTRA_STREAM,Uri.parse("android.resource://com.my.android.sharesound/"+resId));
    startActivity(Intent.createChooser(shareIntent,"Share Sound");

When i select any Mail application eg. Gmail or YahooMail from the Share Intent, the mp3 file attached successfully. But it shows that 2130968609(as an attachment)

i dont want resourceId(2130968609) to appear.

I want to display fileName.mp3

How can i do that? Am i missing something ?

OR

Is there any other way to attach .mp3 file stored in res/raw to mail via Share Intent.

Upvotes: 75

Views: 101640

Answers (7)

Dewey Reed
Dewey Reed

Reputation: 4956

Don't construct string on your own, use Uri.Builder:

/**
 * @param resourceId identifies an application resource
 * @return the Uri by which the application resource is accessed
 */
internal fun Context.getResourceUri(@AnyRes resourceId: Int): Uri = Uri.Builder()
    .scheme(ContentResolver.SCHEME_ANDROID_RESOURCE)
    .authority(packageName)
    .path(resourceId.toString())
    .build()

From AOSP-DeskClock.

Upvotes: 17

Radesh
Radesh

Reputation: 13555

One line Answer

RingtoneManager.getRingtone(getContext(),Uri.parse("android.resource://com.my.package/" + R.raw.fileName)).play();

Upvotes: 2

user9566632
user9566632

Reputation:

Here are some methods that might help someone:

    public Uri getRawUri(String filename) {
        return Uri.parse(ContentResolver.SCHEME_ANDROID_RESOURCE + File.pathSeparator + File.separator + getPackageName() + "/raw/" + filename);
    }
    public Uri getDrawableUri(String filename) {
        return Uri.parse(ContentResolver.SCHEME_ANDROID_RESOURCE + File.pathSeparator + File.separator + getPackageName() + "/drawable/" + filename);
    }
    public Uri getMipmapUri(String filename) {
        return Uri.parse(ContentResolver.SCHEME_ANDROID_RESOURCE + File.pathSeparator + File.separator + getPackageName() + "/mipmap/" + filename);
    }

Just call the method like this:

Uri rawUri = getRawUri("myFile.filetype");

Upvotes: 8

Remario
Remario

Reputation: 3863

Here is a clean way to get any resource,

 Uri.parse(String.format("android.resource://%s/%s/%s",this.getPackageName(),"resource_folder_name","file_name"));

Upvotes: 1

Andrew Sam
Andrew Sam

Reputation: 479

This work like magic: Assuming the mp3 is saved in the raw folder as

notification_sound.mp3

then simple doing this works:

Uri uri=Uri.parse("android.resource://"+getPackageName()+"/raw/notification_sound");

Upvotes: 47

Kartik Domadiya
Kartik Domadiya

Reputation: 29968

Finally after searching a lot i found the solution.

If you want to get any resource URI then there are two ways :

  1. Using Resource Name

    Syntax : android.resource://[package]/[res type]/[res name]

    Example : Uri.parse("android.resource://com.my.package/drawable/icon");

  2. Using Resource Id

    Syntax : android.resource://[package]/[resource_id]

    Example : Uri.parse("android.resource://com.my.package/" + R.drawable.icon);

This were the examples to get the URI of any image file stored in drawable folder.

Similarly you can get URIs of res/raw folder.

In my case i used 1st way ie. Using Resource Name

Upvotes: 185

Reno
Reno

Reputation: 33792

Try saving the file to your SDCard and maybe then send the new URI, 

 public boolean saveAs(int resSoundId){
 byte[] buffer = null;
 InputStream fIn = getBaseContext().getResources().openRawResource(resSoundId);
 int size=0;

 try {
  size = fIn.available();
  buffer = new byte[size];
  fIn.read(buffer);
  fIn.close();
 } catch (IOException e) {
  // TODO Auto-generated catch block
  return false;
 }

 String path = "/sdcard/yourapp/temp/";
 String filename = "filename"+".mp3";

 boolean exists = (new File(path)).exists();
 if (!exists){new File(path).mkdirs();}

 FileOutputStream save;
 try {
  save = new FileOutputStream(path+filename);
  save.write(buffer);
  save.flush();
  save.close();
 } catch (FileNotFoundException e) {
  // TODO Auto-generated catch block
  return false;
 } catch (IOException e) {
  // TODO Auto-generated catch block
  return false;
 }

Remember to delete the file after the email is sent successfully.

Upvotes: 0

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