CODEWITHSUNDEEP
javaandroid
Since_2008
Since_2008

Reputation: 2341

iterate through images

I have 100 images, each is an image of a percentage, for example, 1%, 2%, 3%, etc.

What's the best way to go through each image? Should I add each image resource to a List or Dictionary(if that exists in Android). Or am I forced to hard code it?

public void ShowCircle(final int percentage){
    final ImageView ring = (ImageView)findViewById(R.id.ring);
    ring.setOnClickListener(new View.OnClickListener() {

            public void onClick(View v) {
                // TODO Auto-generated method stub
                for(int i = 0; i != percentage; i++)

                            //I was thinking here I can access list/dictionary records.
                ring.setImageResource(R.drawable.percent_1);
            }
        });
}

Upvotes: 3

Views: 3432

Answers (3)

Matt Ball
Matt Ball

Reputation: 359796

At OP's request, answering with a copypasta from a comment:

Have a look at How do I iterate through the id properties of R.java class? and Android: Programatically iterate through Resource ids.

...though this question should really just be closed as a dup.

Upvotes: 1

Will Jamieson
Will Jamieson

Reputation: 926

I would put them into an array like this

public static int[] picArray = new int[100];
picArray[0] = R.raw.img1;
picArray[1] = R.raw.img2;
//etc

and iterate through them like this

public void onClick(View view) 
{

    ImageView image = (ImageView) findViewById(R.id.imageView1);

    if(counter== (picArray.length - 1) )
    {
        counter =0;


    }
    else
    {
        counter++;

    }
    image.setImageResource(picArray[counter].getImg());

}

Upvotes: 0

Manuel
Manuel

Reputation: 10303

You can put them in an array (info on how to add to an array is found here) and then iterate trhough them with an foreach loop like so:

for(ImageView image : ImageArray) {
    // Do stuff with your image that is now in the variable called image. 
    // All images will be called in the order that they are positioned in the array
}

Upvotes: 1

Related Questions