CODEWITHSUNDEEP
python
purga
purga

Reputation: 453

How to change data in the container while iterating in python

Given the following example:

container = [ (1, "a") , 
              (40, "b") ,
              (24, "c") ,  #we intend to change this
              (103, "d")
            ]

for k,v in container:
    if k == 24:
        v += " good"

print container

The (24, "c") data pair in container will still remain its original value, and won't be changed to (24, "c good"). What would be the way to alter it to (24, "c good") as intended during the iteration?

I use python 2.7 , but 3.x examples are also welcome.

Thanks.

Upvotes: 1

Views: 409

Answers (2)

Tom Ray
Tom Ray

Reputation: 131

Messed up a bit. Fixed now

container = [ (1, "a") , 
                  (40, "b") ,
                  (24, "c") ,  #we intend to change this
                  (103, "d")
                ]

for k, n in enumerate(container):
    if n[0] == 24:
        container[k] = (n[0], n[1] + " good")

print container

Upvotes: 1

sth
sth

Reputation: 229934

You can use enumerate() the keep track of the index of the container item you are looking at:

for i, (k,v) in enumerate(container):
    if k == 24:
        container[i] = (k, v+" good")

Upvotes: 6

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