CODEWITHSUNDEEP
phpxmlrss-reader
omnath
omnath

Reputation: 509

Access image url in a variable

I'm reading a rss feed and I get an image url and now I want to store this image in my folder. For this I'm using 

$image=$movies->channel->item[i]->medium_image_url;

when I

echo $image

it shows http://showmycode.co.in/supermob/app/webroot/img/uploads/product_images/medium/0a646_Bombay-Biryani1.jpg

then I put I $url

$url = '$image';

$img = 'images/'.time().'.'.'jpg';
file_put_contents($img, file_get_contents($url));

and I 

echo $url its show  only $image;

and I found a error

Warning: file_get_contents($image) [function.file-get-contents]: failed to open stream:
               No such file or directory in D:\wamp\www\test_om\rss\rssfeed.php on line 36

How can I store this image?

Upvotes: 0

Views: 673

Answers (1)

Jose
Jose

Reputation: 3558

I think the error is here: 

$url = '$image';

Remove the quotes and try this instead: 

$url = $image;

Upvotes: 3

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