CODEWITHSUNDEEP
phpurl
Lina
Lina

Reputation: 627

PHP current url issue

I'm trying to get current page url. Here is the code:

$url = (!empty($_SERVER['HTTPS'])) ? "https://".$_SERVER['SERVER_NAME'].$_SERVER['REQUEST_URI'] : "http://".$_SERVER['SERVER_NAME'].$_SERVER['REQUEST_URI'];

It works fine. But I'm dealing with problem:

<a title="LT" href="<?php echo $url; ?>?lang=lt">LT</a>

When I press "LT" link once again, it gives me result:

http://127.0.0.1/index.php?lang=lt?lang=lt

How to avoid this?

Upvotes: 1

Views: 348

Answers (2)

Muhammad Ashikuzzaman
Muhammad Ashikuzzaman

Reputation: 3153

I found this code very helpful

$protocol = strpos(strtolower($_SERVER['SERVER_PROTOCOL']),'https') === 
FALSE ? 'http' : 'https';            // Get protocol HTTP/HTTPS
$host     = $_SERVER['HTTP_HOST'];   // Get  www.domain.com
$script   = $_SERVER['SCRIPT_NAME']; // Get folder/file.php
$params   = $_SERVER['QUERY_STRING'];// Get Parameters occupation=odesk&name=ashik

$currentUrl = $protocol . '://' . $host . $script . '?' . $params; // Adding all

echo $currentUrl;

Upvotes: 0

Lucas
Lucas

Reputation: 10646

$_SERVER['REQUEST_URI'] returns everything after the domain including the querystring (Well... not everything, since it can't return fragments...)

If you want to use $_SERVER['REQUEST_URI'] then you could explode it like so:

$uri = explode('?', $_SERVER['REQUEST_URI']);
$uri = $uri[0];

And then use the $uri variable in place of $_SERVER['REQUEST_URI'] like this:

$url = (!empty($_SERVER['HTTPS'])) ? "https://".$_SERVER['SERVER_NAME'].$uri : "http://".$_SERVER['SERVER_NAME'].$uri;

Upvotes: 4

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