CODEWITHSUNDEEP
phpxmlcurl
Manish Jangir
Manish Jangir

Reputation: 5437

Parse XML api using curl

i am trying to parse a xml data using the an api url which i have used in the following code. when i run this url directly in the browser it gives me a xml formatted data like below.

<Error>
<Code>AccessDenied</Code>
<Message>Access Denied</Message>
<RequestId>B4DE627B9936548B</RequestId>
<HostId>LyB4mVbYLYF/a26Wn04sSuMlTwQjLozl11O9Ql2YbMwHgenXRUCd7WAn5QPRa6nj</HostId>
</Error>

but i want this xml in an array then i will itrate that array using foreach loop. 

curl_setopt($ch, CURLOPT_URL,'http://mybucket.s3.amazonaws.com  
/11111.mpg&mpaction=convert%20format=flv');

curl_setopt($ch, CURLOPT_CONNECTTIMEOUT, 2);

curl_setopt($ch, CURLOPT_RETURNTRANSFER, 1);

curl_setopt($ch, CURLOPT_USERAGENT, 'Your application name');

$query = curl_exec($ch);

curl_close($ch);

echo $query;

?>

when i print the variable $query it gives me only the text of xml. i want this xml in an array. please help me

Upvotes: 0

Views: 525

Answers (2)

hakre
hakre

Reputation: 198214

To convert the XML into an array, as alexn already suggested, you can make use of simplexml_load_string and cast it's return value to an array:

$array = (array) simplexml_load_string($query);
print_r($array);

That gives you:

Array
(
    [Code] => AccessDenied
    [Message] => Access Denied
    [RequestId] => B4DE627B9936548B
    [HostId] => LyB4mVbYLYF/a26Wn04sSuMlTwQjLozl11O9Ql2YbMwHgenXRUCd7WAn5QPRa6nj
)

Which might be exactly what you're looking for.

Upvotes: 0

alexn
alexn

Reputation: 59002

CURL is not used for pasing data. You'll have to resort to some library for that. For your case, i recommend using SimpleXML. Example:

$xml = simplexml_load_string($query);
var_dump($xml);

You can then access the various properties using standard array indexes:

echo $xml['Message']; // Yields "Access Denied"

Upvotes: 1

Related Questions