CODEWITHSUNDEEP
java
Alon
Alon

Reputation: 3906

Java Integer.parseInt failed to parse a string

I'm parsing a string of 15 digits like this:

String str = "100004159312045";
int i = Integer.parseInt(str);

I'm getting an exception when doing so. Why? What are the limitations for Integer.parseInt? What other options do I have for converting such long string to a number?

Upvotes: 13

Views: 30650

Answers (5)

wannik
wannik

Reputation: 12756

The range of int is between Integer.MAX_VALUE and Integer.MIN_VALUE inclusive (i.e. from 2147483647 down to -2147483648). You cannot parse the int value of out that range.

You can use long m = Long.parseLong(str); or BigInteger b = new BigInteger(str); for large integer.

Upvotes: 4

Petar Ivanov
Petar Ivanov

Reputation: 93090

int is 32 signed bit, its max value is 2^31-1 = 2147483647

Upvotes: 5

ratchet freak
ratchet freak

Reputation: 48226

because int's maximum value is a little above 2,000,000,000

you can use long or BigInteger

long has double the digits it can store (the max value is square that of int) and BigInteger can handle arbitrarily large numbers

Upvotes: 5

Tim Bender
Tim Bender

Reputation: 20442

The value you are trying to parse exceeds the maximum size of an Integer.

Upvotes: 3

Mark Byers
Mark Byers

Reputation: 839124

Your number is too large to fit in an int which is 32 bits and only has a range of -2,147,483,648 to 2,147,483,647.

Try Long.parseLong instead. A long has 64 bits and has a range of -9,223,372,036,854,775,808 to 9,223,372,036,854,775,807.

Upvotes: 33

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