Reputation: 14286
I need to write an XSLT template to identify a string of numbers. How can i do that?
Upvotes: 1
Views: 3010
Reputation: 243479
XSLT 1.0 solution:
<xsl:stylesheet version="1.0"
xmlns:xsl="http://www.w3.org/1999/XSL/Transform">
<xsl:output omit-xml-declaration="yes" indent="yes"/>
<xsl:strip-space elements="*"/>
<xsl:param name="pNumbers" select="'2,23,12,251'"/>
<xsl:template match="/">
<xsl:call-template name="classify"/>
</xsl:template>
<xsl:template name="classify">
<xsl:param name="pNums" select="$pNumbers"/>
<xsl:if test="string-length($pNums)">
<xsl:variable name="vN" select=
"substring-before(concat($pNums, ','), ',')"/>
<num odd="{$vN mod 2 = 1}">
<xsl:value-of select="$vN"/>
</num>
<xsl:call-template name="classify">
<xsl:with-param name="pNums" select=
"substring-after($pNums, ',')"/>
</xsl:call-template>
</xsl:if>
</xsl:template>
</xsl:stylesheet>
when this transformation is applied on any XML document (not used), the wanted, correct classification is produced:
<num odd="false">2</num>
<num odd="true">23</num>
<num odd="false">12</num>
<num odd="true">251</num>
Upvotes: 1
Reputation: 163352
To split the string into a sequence of numbers, use tokenize()
in XSLT 2.0, or the EXSLT str:tokenize
in XSLT 1.0. To test whether a number $N is even, use $N mod 2 = 0
Upvotes: 2