UcanDoIt
UcanDoIt

Reputation: 1845

Help comparing an argv string

I have:

int main(int argc, char **argv) {
   if (argc != 2) {
      printf("Mode of Use: ./copy ex1\n");
      return -1;
   }

   formatDisk(argv);
}

void formatDisk(char **argv) {
   if (argv[1].equals("ex1")) {
       printf("I will format now \n");
   }
}

How can I check if argv is equal to "ex1" in C? Is there already a function for that? Thanks

Upvotes: 8

Views: 26186

Answers (3)

Poseidon
Poseidon

Reputation: 165

Hello I just wanted to add that my functions arent correctly checking for the strcmp unless I check that they are == 0. Running on Ubuntu 22.04.1 LTS x86_64. code example:

        if (strcmp(argument, ubuntu) == 0)
        {
                system("do stuff");
        }
        else if (strcmp(argument, mac) == 0)
        {
                system("do other stuff")
        }

Upvotes: 0

Zv_oDD
Zv_oDD

Reputation: 1878

Just to give and example of using strings and dynamically allocating new strings. Probably useful when you don't know the size of argv[?]

// Make the string with the value you want compared
char testString[] = "-command";

// Make a char pointer, use new to allocate the memory 
//  the size is determined by string length of argv[1]
char * strToTest = new char[ strlen( argv[1] ) ];

// Now we can copy the contents of argv[1] into strToTest as they are equal size
strcpy( strToTest, argv[1] );

// Now strcmp returns True if the two strings match
if (strcmp( testString, strToTest ) {
//do somthing here ...
}

Upvotes: 2

Dave
Dave

Reputation: 10575

#include <string.h>
if(!strcmp(argv[1], "ex1")) {
    ...
}

Upvotes: 25

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