CODEWITHSUNDEEP
javaarraysstring
Coombes
Coombes

Reputation: 203

Comparing a String to an array of strings

Right basically what I'm trying to do is a very simple login screen to get to know swing.

My issue is I currently have a file pass.txt which is formatted like so:

Username = bob,tony,mike
Password = pass,pass2,pass3

in my Java file I get the strings by using:

String[] user = prop.getProperty("Username").split(",");

Now I then compare this with my text input from a JTextField however it always fails what I have is:

if (input2.equals(pass) && userin.getText().equals(user))

Now I'm guessing my issue is I have an array of strings and it's comparing it to a single string now what I want to do is go through the array and if any of them match I want it to take that match and use it if that makes sense, is there any way to go about this?

Upvotes: 1

Views: 1226

Answers (4)

Jon Newmuis
Jon Newmuis

Reputation: 26530

Assuming you have a pass array to match your user array, and every entry in user is guaranteed to have a corresponding entry in pass, then the following solution should work:

int index = Arrays.asList(user).indexOf(userin.getText());
String password = pass[index];

if (password.equals(input2)) {
    // Successful authentication
} else {
    // Authentication failed
}
  • Arrays.asList(user).indexOf(userin.getText()) will get the index of the user in the list (in your example, "bob" => 0; "tony" => 1; "mike" => 2).
  • password is then the password string at that same index (in your example, "pass" => 0; "pass2" =>1; "pass3" => 2).
  • Then the if compares the password associated with the user (password) with the password that was input in the dialog (input2).

Upvotes: 4

znarf
znarf

Reputation: 814

i think this may help you,because i think you have to check each user with his password int this array:

for(int i=0;i < user.size();i++){
  if(input2.equals(pass[i]) && userin.getText().equals(user[i])){
   //your code
  }
}

Upvotes: 6

jli
jli

Reputation: 6623

You have to somehow search the array for the string you're looking for. There are a bunch of ways of doing this, I'll outline one method.

int index = 0;
for (String s : user) {
    if (s.equals(userin.getText()) {
        // the username matches! now check to see if the password at the _same index_ matches
        if (pass[index].eqals(input2.getText()) {
            // correct username and password!
        } else {
            // bad password!
        }
    }
    ++index;
}

I'm assuming that you have a password array called pass and that the indices match those of the user array. (user[i]'s password is pass[i])

Upvotes: 0

soulcheck
soulcheck

Reputation: 36777

You'll have to search the username table, find the position of introduced username and then check if the password on that position is equal to what the user introduced.

Upvotes: 0

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