Reputation: 171321
To get all jobs which invoice_number
is a pure number I do:
Job.where("invoice_number REGEXP '^[[:digit:]]+$'")
Is it possible to do the same by specifying the regex in Ruby rather than MySQL ?
Upvotes: 13
Views: 8566
Reputation: 1411
we can write like
scope :only_valid_email_record , :conditions=>["email_id ~ ?","^([a-zA-Z0-9_.'-])+@(([a-zA0-9-])+.)+([a-zA-Z0-9]{2,4})+$"]
It works fine in rails 3.
Upvotes: 1
Reputation: 37517
One way is
Job.all.select{|j| j =~ /^\d+$/}
but it will not be as efficient as the MySQL version.
Another possibility is to use a named scope to hide the ugly SQL:
named_scope :all_digits, lambda { |regex_str|
{ :condition => [" invoice_number REGEXP '?' " , regex_str] }
}
Then you have Job.all_digits
.
Note that in the second example, you are assembling a query for the database, so regex_str
needs to be a MySQL regex string instead of a Ruby Regex object, which has a slightly different syntax.
Upvotes: 13
Reputation: 22721
Your best bet is either Regexp#tos or Regexp#source or Regexp#inspect.
But I can't think of why you would want to do this -- Ruby doesn't make it easy to compose Regexp
s programmatically (which is the only reason I can think of why one might want to compose at one level and submit it to another).
Upvotes: 2