Reputation: 9647
Is there any php function available where I can add days to a date to make up another date? For example, I have a date in the following format: 27-December-2011
If I add 7 to the above, it should give: 03-January-2012.
Many thanks
Upvotes: 14
Views: 41620
Reputation: 1237
$registered = $udata->user_registered;
$registered = date( "d m Y", strtotime( $registered ));
$challanexpiry = explode(' ', $registered);
$day = $challanexpiry[0];
$month = $challanexpiry[1];
$year = $challanexpiry[2];
$day = $day+10;
$bankchallanexpiry = $day . " " . $month . " " . $year;
Upvotes: 0
Reputation: 1336
Actually it's easier than all that.
$some_var = date("Y-m-d",strtotime("+7 day"))
You can use a variable instead of the string, of course. It will be great if the people answering the questions, won't complicate things. Less code, means less time to waste on the server ;).
Upvotes: 2
Reputation: 22142
You can use the add method of DateTime. Anyway this solution works for php version >= 5.3
Upvotes: 5
Reputation: 21262
Look at this simple snippet
$date = date("Y-m-d");// current date
$date = strtotime(date("Y-m-d", strtotime($date)) . " +1 day");
$date = strtotime(date("Y-m-d", strtotime($date)) . " +1 week");
$date = strtotime(date("Y-m-d", strtotime($date)) . " +2 week");
$date = strtotime(date("Y-m-d", strtotime($date)) . " +1 month");
$date = strtotime(date("Y-m-d", strtotime($date)) . " +30 days");
Upvotes: 9
Reputation: 48284
$date = new DateTime('27-December-2011');
$date->add(new DateInterval('P7D'));
echo $date->format('d-F-Y') . "\n";
Change the format string to be whatever you want. (See the documentation for date()
).
Upvotes: 1
Reputation: 3776
Try this
$add_days = 7;
$date = date('Y-m-d',strtotime($date) + (24*3600*$add_days));
Upvotes: 18