Reputation: 249
I have data = [1 1.2 1.3 1.5 1.8]
I want to find closest values before and after from data for this point, b = 1.23
How do I do this?
Upvotes: 22
Views: 33611
Reputation: 1844
This might be a little bit hacky and inefficient, but I use interp1
to find the single closest value as follows:
nearestTo = @(x, xq) interp1(x, x, xq, 'nearest');
nearestTo([2 4 6 8 10], [pi 2*pi 3*pi]) % 4 6 10
nearestTo(sort([2 7 11 3 5]), abs(-3.5)) % 3
Upvotes: 1
Reputation: 121
This method generalizes Doubt's answer to the case where there are multiple elements in b
that you are searching for:
ind=knnsearch(data',b)
c=data(ind)
which returns the index (or array of indices), ind
, of the closest element (or elements) in data
to the elements listed in b
.
Note that data is transposed because the set to be searched in needs to be a column vector. If be had multiple elements then it should also be a column vector.
Also, this method can be generalized to give 2nd, 3rd, 4th ... closest neighbors (see documentation).
It also generalizes to the case when the data is higher dimensional (If d
dimensions then test
and b
would have d
columns).
Upvotes: 2
Reputation: 1349
data = [1 1.2 1.3 1.5 1.8]
b = 1.23
find(abs(data-b)==min(abs(data-b)))
Upvotes: 0
Reputation: 1222
Here is another method. The vector data
need not be sorted and b
can be positive or negative.
[~,I] = min(abs(data-b));
c = data(I);
Upvotes: 23
Reputation: 4732
if the data is sorted you can use find:
i_lower = find(data <= b,1,'last');
i_higher = find(data >= b,1,'first');
lower_than_b = data(i_lower)
higher_than_b = data(i_higher)
Upvotes: 11