CODEWITHSUNDEEP
phpparametersreference
user893856
user893856

Reputation: 1029

php, I cant pass an array as reference

this is the function:

public function func(&$parameters = array())
{
}

now I need to do this:

$x->func (get_defined_vars());

but that fails. Another way:

$x->func (&get_defined_vars());

it drops an error: Can't use function return value in write context in ...

Then how to do it?

Upvotes: 1

Views: 434

Answers (3)

NikiC
NikiC

Reputation: 101936

get_defined_vars() returns an array, not a variable. As you can only pass variables by reference you need to write:

$definedVars = get_defined_vars();
func($definedVars);

Though I don't really see a reason to pass the array by reference here. (If you are doing this for performance, don't do it, as it won't help.)

Upvotes: 6

Siva Charan
Siva Charan

Reputation: 18064

Try this way:-

call_user_func_array( 'func', $parameters );

See the notes on the call_user_func_array() function documentation for more information.

Upvotes: 1

abhinav
abhinav

Reputation: 3217

public  function func(&$parameters = array())
{
}

Not defined correctly.

Upvotes: 3

Related Questions