Reputation: 5235
I have a very simple example of a menu here:
<ul id="1">
<li><a href="#">First</a></li>
<li><a href="#">Second</a>
<ul id="2">
<li><a href="#">Second - 1</a></li>
<li><a href="#">Second - 2</a></li>
<li><a href="#">Second - 3</a>
<ul id="3">
<li><a href="#">Aaa</a></li>
<li><a href="#">Bbb</a></li>
<li><a href="#">Ccc</a></li>
</ul>
</li>
</ul>
</li>
<li><a href="#">Third</a></li>
</ul>
I need to get the <li>
that has a child <ul>
and that is a child of <ul>
who is a child of <li>
, and apply a style to it.
I know it sounds complicated, but in the example above I want to get only the <li>
that says "Second - 3" which is inside a ul, which is a child of a li and has a child ul. I don't want to get any other <li>
s.
I can't do this without getting also the li which says "Second", and I don't want that.
$("li > ul").addClass('whatever');
Upvotes: 0
Views: 1055
Reputation: 11
Unless I get you wrong this is simple. Try something like this:
$('#3').parent('li').addClass('whatever');
This will select the parent node of the ul
element with the id = 3 (only if it is an li
element)
Upvotes: 1
Reputation: 2021
Try this:
$("li > ul > li").each(function(){
if ( $(this).find("ul").length > 0){
$(this).css({"font-weight":"bold"});
}
});
Upvotes: 1
Reputation: 82893
Use $("li ul li:has(ul)")
e.g:
$(function(){
var items = $("li ul li:has(ul)");
alert(items.html());
});
Working example: http://jsfiddle.net/EXzaa/
Upvotes: 6