Reputation: 1481
Is there any way in C++ to check whether a string starts with a certain string (smaller than the original) ? Just like we can do in Java
bigString.startswith(smallString);
Upvotes: 58
Views: 87518
Reputation: 8758
With C++20 you can use std::basic_string::starts_with
(or std::basic_string_view::starts_with
):
#include <string_view>
std::string_view bigString_v("Winter is gone"); // std::string_view avoids the copy in substr below.
std::string_view smallString_v("Winter");
if (bigString_v.starts_with(smallString_v))
{
std::cout << "Westeros" << bigString_v.substr(smallString_v.size());
}
Upvotes: 5
Reputation: 18964
You can do this with string::compare()
, which offers various options for comparing all or parts of two strings. This version compares smallString
with the appropriate size prefix of bigString
(and works correctly if bigString
is shorter than smallString
):
bigString.compare(0, smallString.length(), smallString) == 0
I tend to wrap this up in a free function called startsWith()
, since otherwise it can look a bit mysterious.
UPDATE: C++20 is adding new starts_with
and ends_with
functions, so you will finally be able to write just bigString.starts_with(smallString)
.
Upvotes: 70
Reputation: 5205
To optimize a little bit:
if ( smallString.size() <= bigString.size() &&
strncmp( smallString.c_str(), bigString.c_str(), smallString.length() ) == 0 )
Don't forget to #include <cstring>
or #include <string.h>
Upvotes: 4
Reputation: 1203
I thought it makes sense to post a raw solution that doesn't use any library functions...
// Checks whether `str' starts with `start'
bool startsWith(const std::string& str, const std::string& start) {
if (&start == &str) return true; // str and start are the same string
if (start.length() > str.length()) return false;
for (size_t i = 0; i < start.length(); ++i) {
if (start[i] != str[i]) return false;
}
return true;
}
Adding a simple std::tolower
we can make this case insensitive
// Checks whether `str' starts with `start' ignoring case
bool startsWithIgnoreCase(const std::string& str, const std::string& start) {
if (&start == &str) return true; // str and start are the same string
if (start.length() > str.length()) return false;
for (size_t i = 0; i < start.length(); ++i) {
if (std::tolower(start[i]) != std::tolower(str[i])) return false;
}
return true;
}
Upvotes: 0
Reputation: 32635
The correct solution, as always, comes from Boost: boost::algorithm::starts_with
.
Upvotes: 9
Reputation: 6786
strstr()
returns a pointer to the first occurrence of a string within a string.
Upvotes: 1
Reputation: 153929
The simplest approach would be:
if ( smallString.size() <= bigString.size()
&& std::equals( smallString.begin(), smallString.end(), bigString.end() )
(This will also work if one of the two, or both, is a vector. Or any other standard container type.)
Upvotes: 1
Reputation: 7985
The approaches using string::find()
or string::substr()
are not optimal since they either make a copy of your string, or search for more than matches at the beginning of the string. It might not be an issue in your case, but if it is you could use the std::equal
algorithm. Remember to check that the "haystack" is at least as long as the "needle".
#include <string>
using namespace std;
bool startsWith(const string& haystack, const string& needle) {
return needle.length() <= haystack.length()
&& equal(needle.begin(), needle.end(), haystack.begin());
}
Upvotes: 32
Reputation: 39294
http://www.cplusplus.com/reference/string/string/substr/
You can use string.substr() to see any number of characters from any position, or you could use a string.find() member.
Upvotes: -1
Reputation: 17732
Either create a substring that is the length of your smallString
variable, and compare the two. Or do a search for the substring smallString
and see if it returns index 0
Upvotes: -1
Reputation: 409196
std::string s("Hello world");
if (s.find("Hello") == 0)
{
std::cout << "String starts with Hello\n";
}
Upvotes: 89