CODEWITHSUNDEEP
phpjqueryajax
FrogSkin
FrogSkin

Reputation:

Is this a jQuery bug, or am I missing something?

I am using jquery-1.3.2 in an AJAX web application. I use the jQuery ajax $.post() method to submit requests to the server.

On the server I am using php to build an array and then json_encode the answer. Then on the client I use the callback function of the AJAX post method to process the response.

All works well until I use the $.post() method to send variables to the server. If I send variables to the server, the response I get back is [object Object] and therefore I am unable to parse it. I have a work around at the moment that when posting variables I request a HTML response and then I parse that.

So the code involved taken from my site is:

The Jax call: 

$.post("inc/sendfeedback.php", {NAME: name,TYPE: type,EMAIL: email,COMMENT: comment}, function(data) {PostData(data);}, "json");

So the PostData code looks like this:

function ProcessData(data)
{
    //alert(data);
    var jo = eval("(" + data + ")");
    if(jo.result == "true")
    {
        if(jo.data != "" && jo.element != "")
        {
            $(jo.element).html(jo.data);
        }
    }

    SMessage(jo.error);
}

If I uncomment the above code the alert with have in it [object Object].

if I remove the Post variables from the call it works fine.

The server code look like this:

$arr = array ("result" => $result,"data" => $data,"error" => $error,"element" => $element);
echo(json_encode($arr));

Is this a bug with the jQuery library, I tried it with the 1.2 version however its was still present there? I also search the jQuery site and can not find anyone having this issue.

So I assume I am missing something. But what?

Upvotes: 0

Views: 472

Answers (3)

FrogSkin
FrogSkin

Reputation:

I have since registered and now can't post comments into this thread without reputation and can not see any easy method to claim this question as mine.

Deviant, your suggestion of using the $.ajax() method worked. Reason it didnt work for me the first time was I submitted the post data as a JSON object when the server code was expecting POST data.

So I fixed my javascript to call the server script correctly and everything works exactly as it should.

So the conclusion is, the $.post() method has a bug in it. I have not tracked it down but line 3633 is were the post method makes the call. I started digging however have not yet found the issue.

I qualify this by the fact the $.ajax() to the same server script and the same javascript processes the response and it all works, use the $.post method and my script fails with the return even through the return object appears to be a valid JSON object.

Thanks for the help guys. Now to go and remove all my $.post calls for $.ajax calls.

The result of all this can be seen at www.pygames.net

Cheers Shane a.k.a FrogSkin

Upvotes: 0

Jordan S. Jones
Jordan S. Jones

Reputation: 13883

Because you are using an associative PHP array, json_encode will return a string representation of a Javascript Object and not a Javascript Array. However, you should still be able to process it in a similar fashion to an array:

for (var key in data)
{
    var item = data[key];
}

I would strongly recommend you download Firefox+Firebug addon and use the console API for debugging/dumping what is being returned by the server.

Upvotes: 1

Chad Grant
Chad Grant

Reputation: 45382

$.ajax({
      url: "script.php",
      global: false,
      type: "POST",
      data: {NAME: name,TYPE: type,EMAIL: email,COMMENT: comment},
      dataType: "json",
      contentType: "application/json",
      success: function(data){
         alert(data.result);
      }
   }

No need to eval, jQuery evals/parses it before calling the success callback.

eval = pure evil

http://docs.jquery.com/Ajax/jQuery.ajax#options

Upvotes: 5

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