Get the last non-empty cell in a column in Google Sheets

Question

I use the following function

=DAYS360(A2, A35)

to calculate the difference between two dates in my column. However, the column is ever expanding and I currently have to manually change 'A35' as I update my spreadsheet.

Is there a way (in Google Sheets) to find the last non-empty cell in this column and then dynamically set that parameter in the above function?

Answer 1

getting the last non-empty row number can be done with:

=INDEX(XMATCH(, (B:B<>"")-1,, -1))

alternatives:

=INDEX(LET(x, B:B, MAX(IF(x<>"", ROW(x)))))

=INDEX(LET(x, B:B, LOOKUP(9, 1/(x<>""), ROW(x))))

=INDEX(LET(x, B:B, LOOKUP(9^9, x, ROW(x))))

=INDEX(LET(x, B:B, MATCH(9^9, x)))     

 // last two work only if the last value in a column is numeric

Answer 2

This problem can now be easily solved using the recently released TOCOL and CHOOSEROWS functions.

=CHOOSEROWS(TOCOL(A2:A,1),-1)

The TOCOL function with second argument set to 1 removes the blank values in the range A2:A and the CHOOSEROWS function with second argument set to -1 returns the first value from the bottom (i.e. the last value).

The same formula can also be used to return the last non-empty value from a row:

Note: In order for this formula to work, the empty values in the range must be actual empty values, not empty strings "". If the range contains empty strings, use the following formula instead:

=CHOOSEROWS(FILTER(A2:A,A2:A<>""),-1)

Answer 3

This worked for me: =ArrayFormula(LOOKUP(2,1/(CELL_RANGE<>""),CELL_RANGE))

Just put the range of your cells in CELL_RANGE.

In addition to this working on a single column, also works on a single row.

Answer 4

With the introduction of LAMBDA and REDUCE functions we can now compute the row number in a single pass through the cells (Several of the solutions above filter the range twice.) and without relying on magic text or numeric values.

=lambda(rng, 
   REDUCE(0, rng, lambda(maxrow, cell, if(isblank(cell),maxrow,row(cell)) ) )
)(A:A)

which can be nicely packaged into a Named Function for usage like

=LAST_ROWNUM(A:A)

It works on columns with interspersed blanks, and multi-column ranges (because REDUCE iterates over the range in row-first), and partial columns (like A20:A), still returning the actual row number (not the offset within the range).

This can then be combined with Index to return the value

=DAYS360(A2, Index(A1, LAST_ROWNUM(A:A)))

---

(In truth, though, I suspect that the OPs date values are monotonic (even if with blanks in between), and that he could get away with

=DAYS360(A2, MAX(A2:A))

This solution is identified above as relying on the dates being "contiguous" - whether that means "no blanks" or "no missing dates" I'm not certain - but either stipulation is not necessary.)

Answer 5

Although the question is already answered, there is an eloquent way to do it.

Use just the column name to denote last non-empty row of that column.

For example:

If your data is in A1:A100 and you want to be able to add some more data to column A, say it can be A1:A105 or even A1:A1234 later, you can use this range:

A1:A

So to get last non-empty value in a range, we will use 2 functions:

• COUNTA
• INDEX

The answer is =INDEX(B3:B,COUNTA(B3:B)).

Here is the explanation:

COUNTA(range): Returns number of values in a range, we can use this to get the count of rows.

INDEX(range, row, col): Returns the content of a cell, specified by row and column offset. If the column is omitted then the whole row is returned.

Examples:

INDEX(A1:C5,1,1) = A1
INDEX(A1:C5,1) = A1,B1,C1 # Whole row since the column is not specified
INDEX(A1:C5,1,2) = B1
INDEX(A1:C5,1,3) = C1
INDEX(A1:C5,2,1) = A2
INDEX(A1:C5,2,2) = B2
INDEX(A1:C5,2,3) = C2
INDEX(A1:C5,3,1) = A3
INDEX(A1:C5,3,2) = B3
INDEX(A1:C5,3,3) = C3

For the picture above, our range will be B3:B. So we will count how many values are there in range B3:B by COUNTA(B3:B) first. In the left side, it will produce 8 since there are 8 values while it will produce 9 in the right side. We also know that the last value is in the 1st column of the range B3:B so the col parameter of INDEX must be 1 and the row parameter should be COUNTA(B3:B).

PS: please upvote @bloodymurderlive's answer since he wrote it first, I'm just explaining it here.

Answer 6

To pick the last in a column of arbitrary, non-empty values ignoring the header cell (A1):

=INDEX(A2:A,COUNT(A2:A))

Answer 7

For strictly finding the last non-empty cell in a column, this should work...

=LOOKUP(2^99, A2:A)

Answer 8

This may work:

=DAYS360(A2,INDEX(A2:A,COUNTA(A2:A)))

Answer 9

Ben Collins is a Google sheets guru, he has many tips on his site for free and also offers courses. He has a free article on dynamic range names and I have used this as the basis for many of my projects.

https://www.benlcollins.com/formula-examples/dynamic-named-ranges/

Disclaimer, I have nothing to gain by referring Ben's site.

Here is a screenshot of one of my projects using dynamic ranges:

Cell D3 has this formula which was shown above except this is as an array formula:

=ArrayFormula(MAX(IF(L2s!A2:A1009<>"",ROW(2:1011))))

Cell D4 has this formula:

="L2s!A2:E"&D3

Answer 10

This works for me. Get last value of the column A in Google sheet:

=index(A:A,max(row(A:A)*(A:A<>"")))

(It also skips blank rows in between if any)

Answer 11

This seems like the simplest solution that I've found to retrieve the last value in an ever-expanding column:

=INDEX(A:A,COUNTA(A:A),1)

Answer 12

This will give the contents of the last cell:

=indirect("A"&max(ARRAYFORMULA(row(a:a)*--(a:a<>""))))

This will give the address of the last cell:

="A"&max(ARRAYFORMULA(row(a:a)*--(a:a<>"")))

This will give the row of the last cell:

=max(ARRAYFORMULA(row(a:a)*--(a:a<>"")))

Maybe you'd prefer a script. This script is way shorter than the huge one posted above by someone else:

Go to script editor and save this script:

function getLastRow(range){
  while(range.length>0 && range[range.length-1][0]=='') range.pop();
  return range.length;
}

One this is done you just need to enter this in a cell:

=getLastRow(A:A)

Answer 13

To find last nonempty row number (allowing blanks between them) I used below to search column A.

=ArrayFormula(IFNA(match(2,1/(A:A<>""))))

Answer 14

for a row:

=ARRAYFORMULA(INDIRECT("A"&MAX(IF(A:A<>"", ROW(A:A), ))))

for a column:

=ARRAYFORMULA(INDIRECT(ADDRESS(1, MAX(IF(1:1<>"", COLUMN(1:1), )), 4)))

Answer 15

I went a different route. Since I know I'll be adding something into a row/column one by one, I find out the last row by first counting the fields that have data. I'll demonstrate this with a column:

=COUNT(A5:A34)

So, let's say that returned 21. A5 is 4 rows down, so I need to get the 21st position from the 4th row down. I can do this using inderect, like so:

=INDIRECT("A"&COUNT(A5:A34)+4)

It's finding the amount of rows with data, and returning me a number I'm using as an index modifier.

Answer 16

Calculate the difference between latest date in column A with the date in cell A2.

=MAX(A2:A)-A2

Answer 17

Here's another one:

=indirect("A"&max(arrayformula(if(A:A<>"",row(A:A),""))))

With the final equation being this:

=DAYS360(A2,indirect("A"&max(arrayformula(if(A:A<>"",row(A:A),"")))))

The other equations on here work, but I like this one because it makes getting the row number easy, which I find I need to do more often. Just the row number would be like this:

=max(arrayformula(if(A:A<>"",row(A:A),"")))

I originally tried to find just this to solve a spreadsheet issue, but couldn't find anything useful that just gave the row number of the last entry, so hopefully this is helpful for someone.

Also, this has the added advantage that it works for any type of data in any order, and you can have blank rows in between rows with content, and it doesn't count cells with formulas that evaluate to "". It can also handle repeated values. All in all it's very similar to the equation that uses max((G:G<>"")*row(G:G)) on here, but makes pulling out the row number a little easier if that's what you're after.

Alternatively, if you want to put a script on your sheet you can make it easy on yourself if you plan on doing this a lot. Here's that scirpt:

function lastRow(sheet,column) {
  var ss = SpreadsheetApp.getActiveSpreadsheet();
  if (column == null) {
    if (sheet != null) {
       var sheet = ss.getSheetByName(sheet);
    } else {
      var sheet = ss.getActiveSheet();
    }
    return sheet.getLastRow();
  } else {
    var sheet = ss.getSheetByName(sheet);
    var lastRow = sheet.getLastRow();
    var array = sheet.getRange(column + 1 + ':' + column + lastRow).getValues();
    for (i=0;i<array.length;i++) {
      if (array[i] != '') {       
        var final = i + 1;
      }
    }
    if (final != null) {
      return final;
    } else {
      return 0;
    }
  }
}

Here you can just type in the following if you want the last row on the same of the sheet that you're currently editing:

=LASTROW()

or if you want the last row of a particular column from that sheet, or of a particular column from another sheet you can do the following:

=LASTROW("Sheet1","A")

And for the last row of a particular sheet in general:

=LASTROW("Sheet1")

Then to get the actual data you can either use indirect:

=INDIRECT("A"&LASTROW())

or you can modify the above script at the last two return lines (the last two since you would have to put both the sheet and the column to get the actual value from an actual column), and replace the variable with the following:

return sheet.getRange(column + final).getValue();

and

return sheet.getRange(column + lastRow).getValue();

One benefit of this script is that you can choose if you want to include equations that evaluate to "". If no arguments are added equations evaluating to "" will be counted, but if you specify a sheet and column they will now be counted. Also, there's a lot of flexibility if you're willing to use variations of the script.

Probably overkill, but all possible.

Answer 18

My favorite is:

=INDEX(A2:A,COUNTA(A2:A),1)

So, for the OP's need:

=DAYS360(A2,INDEX(A2:A,COUNTA(A2:A),1))

Answer 19

To find the last non-empty cell you can use INDEX and MATCH functions like this:

=DAYS360(A2; INDEX(A:A; MATCH(99^99;A:A; 1)))

I think this is a little bit faster and easier.

Answer 20

If the column expanded only by contiguously added dates as in my case - I used just MAX function to get last date.

The final formula will be:

=DAYS360(A2; MAX(A2:A)) 

Answer 21

The way an amateur does it is "=CONCATENATE("A",COUNTUNIQUE(A1:A9999))", where A1 is the first cell in the column, and A9999 is farther down that column than I ever expect to have any entries. This resultant A# can be used with the INDIRECT function as needed.

Answer 22

If A2:A contains dates contiguously then INDEX(A2:A,COUNT(A2:A)) will return the last date. The final formula is

=DAYS360(A2,INDEX(A2:A,COUNT(A2:A)))

Answer 23

What about this formula for getting the last value:

=index(G:G;max((G:G<>"")*row(G:G)))

And this would be a final formula for your original task:

=DAYS360(G10;index(G:G;max((G:G<>"")*row(G:G))))

Suppose that your initial date is in G10.

Answer 24

There may be a more eloquent way, but this is the way I came up with:

The function to find the last populated cell in a column is:

=INDEX( FILTER( A:A ; NOT( ISBLANK( A:A ) ) ) ; ROWS( FILTER( A:A ; NOT( ISBLANK( A:A ) ) ) ) )

So if you combine it with your current function it would look like this:

=DAYS360(A2,INDEX( FILTER( A:A ; NOT( ISBLANK( A:A ) ) ) ; ROWS( FILTER( A:A ; NOT( ISBLANK( A:A ) ) ) ) ))