CODEWITHSUNDEEP
pythonpython-3.xfor-loopfloating-pointtypeerror
hamsolo474 - Reinstate Monica
hamsolo474 - Reinstate Monica

Reputation: 695

TypeError: 'float' object not iterable

I'm using python 3.2.2 on windows 7 and I'm trying to create a program which accepts 7 numbers and then tells the user how many are positive, how many are negative and how many are zero. This is what I have got so far:

count=7
for i in count:
    num = float(input("Type a number, any number:"))
    if num == 0:
        zero+=1
    elif num > 0:
        positive+=1
    elif num < 0:
        negative+=1

print (positive)
print (negative)
print (zero)

But when I run the code I get

TypeError: 'float' object is not iterable

If I replace float in line 3 with int I get the same problem except it says that the 'int' object is not iterable. I have also tried changing the value of count from 7 to 7.0. How do I resolve this error?

Upvotes: 30

Views: 289635

Answers (3)

cottontail
cottontail

Reputation: 23081

In short, check if you have unexpected/"hidden" NaN values in the data passed to a function that expects an iterable such as string, list etc.

As the other answers pointed out, this error occurs when your code expects an iterable but a float is passed to it. Missing data is often represented as NaN (which is a float), so if pass float or a NaN to a function that expects an iterable, it throws this error. Apart from the explicit loop (for i in 7.0) in the OP, many of the built-in functions such as list(), set(), tuple(), dict(), enumerate(), all(), any(), max(), min(), sum() etc. expect an iterable, so if you pass a float to them, e.g. max(float('nan')) or list(1.5), you'll get the error in the title.

Upvotes: 0

Mohammad Efazati
Mohammad Efazati

Reputation: 4910

use

range(count)

int and float are not iterable

Upvotes: 4

Thomas K
Thomas K

Reputation: 40340

for i in count: means for i in 7:, which won't work. The bit after the in should be of an iterable type, not a number. Try this:

for i in range(count):

Upvotes: 36

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