CODEWITHSUNDEEP
algorithm
NosiaD
NosiaD

Reputation: 597

Determine day based on number

I just want to ask if how do you determine

Enter a number: 14
Then the date to day is Sunday.

the above demonstration is from 1-7=monday-sunday then if the value is 8 then its monday again...but how could I determine it?using loops and modulo?...

I appreciate any comments for helping me...

any language are ok, I just want to know the algorithm with it...

Upvotes: 0

Views: 144

Answers (9)

Vladislav Bauer
Vladislav Bauer

Reputation: 962

import java.util.Scanner;

public class TestMain {
    private static final String[] DAYS = new String[] { "Sunday", "Monday", "Tuesday", "Wednesday", "Thusday", "Friday", "Saturday" };

    public static void main(final String[] args) {
        System.out.print("Enter a number: ");

        final Scanner scanner = new Scanner(System.in);
        final int n = scanner.nextInt();

        System.out.print("Then the date to day is " + DAYS[n % 7]);
    }
}

Upvotes: 1

COBOLdinosaur
COBOLdinosaur

Reputation: 294

datArr= new Array ('Sun', 'Mon', 'Tue',Wen', 'Thu, 'Fri', 'Sat');
day =datArr[(daynum%7)];

If Sunday gets treated as day zero there is no need to subtract 1 after the modulo. Of course most of the solutions will fail with zero dive if an actual value of zero is encountered.

Upvotes: 1

Eamonn McEvoy
Eamonn McEvoy

Reputation: 8986

string day;
int inputNumber;

if(inputNumber%7 == 0)
  day = "monday";  // or sunday if you prefer :p
else if(inputNumber%7 == 1)
  day = tuesday
...
...
...

Upvotes: 1

Serdar Dogruyol
Serdar Dogruyol

Reputation: 5157

Get modulo 7 of the int value thats passed in and make a switch statement for it.

switch:
   case 1:
    Sunday
   case 2:
    Monday 

    // and so on

Upvotes: 1

John Dibling
John Dibling

Reputation: 101456

In C++, int day = (i-1) % 7; will give you a zero-based offset. Here's sample code:

#include <iostream>
#include<string>

using namespace std;

int main()
{
    static const std::string days [] = 
    {
        "Sunday",
        "Monday",
        "Tuesday",
        "Wednesday",
        "Thursday",
        "Friday",
        "Saturday"
    };

    static const size_t num_days = sizeof(days)/sizeof(days[0]);

    for( int i = 1; i <= 31; ++i )
    {
        int day = (i-1) % 7;
        cout << day << " = " << days[day] << "\n";
    }
}

Upvotes: 1

Niels
Niels

Reputation: 49919

You can just use module

Module got to 0 so it would be something like

<?php
    $value = 13;
    $daynames = array("mon", "tues", "wed", "thur", "fri", "sat", "sun");

    // The + 1 is because % is 0, and you want 1-7
    echo (($value % 7) + 1) .  "day of the week";
    echo "the day is " . $daynames[($value % 7)];
?>

Example: http://codepad.org/wbGuMI06

Upvotes: 2

Jerry Coffin
Jerry Coffin

Reputation: 490058

Taking the number modulo 7 would seem like the obvious possibility.

Upvotes: 1

corsiKa
corsiKa

Reputation: 82559

You can use a switch statement and modulo arithmetic to do this.

The first step to learning computer science is to learn that numbers don't usually start at 1. They start at 0. Getting this idea down will help you tremendously in the future!

// accept numbers 0-6. If 7 were to get put in, it would end up being 0 since 7 % 7 = 0.

switch(num % 7) {
case 0: return "Sunday";
case 1: return "Monday";
case 2: return "Tuesday";
/// rest here...
default: throw new IllegalArgumentException();

}

Upvotes: 1

Marcus
Marcus

Reputation: 12586

If you have a switch/case or if/else for the seven days you can use modulo 7 to get the input into the desired range of 7 days.

Upvotes: 1

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