CODEWITHSUNDEEP
bashsedconfiguration-files
SebastianK
SebastianK

Reputation: 55

Modify key="Value" config with sed

I am trying to write a script that configures a config file used by a nother script. I am trying to use sed like this

sed -c -i "s/\($TARGET_KEY *= *\).*/\1$REPLACEMENT_VALUE/" $CONFIG_FILE

But it's not working as it is intended to it strips the quotation marks and i cant figure out how to write it so it dont.

the second problem is that when i run this on Mac OS the out put is an error:

sed: illegal option -- c
usage: sed script [-Ealn] [-i extension] [file ...]
   sed [-Ealn] [-i extension] [-e script] ... [-f script_file] ... [file ...]

I am new to usage of sed so please forgive my lack of skills in this area.

Upvotes: 4

Views: 10033

Answers (2)

Kent
Kent

Reputation: 195059

see the test below, I didn't add "-i", just print the output. you can add -i if you need:

kent$  cat c.conf 
key1="value1"
foo   =   "fooValue"
bar="barValue"

kent$  echo $k1
foo

kent$  echo $v1
foo_new

kent$  sed -r "s/($k1 *= *\").*/\1$v1\"/" c.conf
key1="value1"
foo   =   "foo_new"
bar="barValue"

Upvotes: 2

OpenSauce
OpenSauce

Reputation: 8623

Have you tried escaping the quotes? This works for me (on Cygwin):

~$ echo -e "key1=\"value1\"\nkey2=\"value2\""
key1="value1"
key2="value2"
~$ TARGET_KEY=key2
~$ REPLACEMENT_VALUE=new_val
~$ echo -e "key1=\"value1\"\nkey2=\"value2\"" | sed "s/\($TARGET_KEY *= *\"\).*/\1$REPLACEMENT_VALUE\"/"
key1="value1"
key2="new_val"
~$

Upvotes: 0

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