CODEWITHSUNDEEP
phploopsforeach
yuli chika
yuli chika

Reputation: 9221

Loop over an array of csv strings containing quoted values then return the first value from each csv string

I am trying loop over an array with a foreach().

When I tested the code below,

$aa = array("'a1','a2'","'b1','b2'","'c1','c2'");
foreach($aa as $bb){
    $cc = array($bb);//var_dump($cc);  (1) { [0]=> string(9) "'a1','a2'" }...
    foreach($cc as $dd){
        echo $dd.'<br />';
        break;
    }
}

It will output:

'a1','a2'
'b1','b2'
'c1','c2'

But I want a1,b1,c1.

Wrong with $cc = array($bb)...

What is the problem?

Upvotes: 0

Views: 221

Answers (2)

mickmackusa
mickmackusa

Reputation: 47873

Iterate over you single quote wrapped csv strings and return the first value from each string after parsing.

Code: (Demo)

$aa = [
    "'a1','a2'",
    "'b1','b2'",
    "'c1','c2'"
];
var_export(
    array_map(
        fn($csv) => str_getcsv($csv, ',', "'")[0],
        $aa
    )
);

If you require a lone delimited string, just call implode() on the result array above.

Upvotes: 0

Oroboros102
Oroboros102

Reputation: 2254

You have one level array, not two. Elements are just strings for php, not arrays. That's why your code doesn't work.

Replace your $cc = array($bb) string with smth like this:

$cc = explode(',', $bb);
foreach($cc as $dd){
    echo trim($dd, "'").'<br />';
    break;
}

Upvotes: 3

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