CODEWITHSUNDEEP
javaregextext-extraction
ganjan
ganjan

Reputation: 7576

How to extract IP:PORT from strings java

I have a text file, and loop though the file like this:

for ( int i = 0; i < this.textLines.size(); i++ ) {
    String tempString = textLines.get( i );

So now I have tempString containing something like:

46.102.241.199:3128 0.2990 Transp. NN N 100% 2011-11-19 17:56:02

What I want to to is return the IP:PORT part, in this case: 46.102.241.199:3128

How can I do that?

Upvotes: 3

Views: 6145

Answers (2)

Mob
Mob

Reputation: 11098

I don't think you need regex for this, this is possible with StringTokenizer.

import java.util.ArrayList;
import java.util.StringTokenizer;

public class SOScrap{
public static void main(String[] args) {
    ArrayList<String> as = new ArrayList<String>();
    ArrayList<String> asa = new ArrayList<String>();
    String s = "46.102.241.199:3128 0.2990 Transp. NN N 100% 2011-11-19 17:56:02";
    StringTokenizer st = new StringTokenizer(s, " ");
        while(st.hasMoreTokens()){
              as.add(st.nextToken());
        }

    StringTokenizer astk = new StringTokenizer(as.get(0), ":");

        while(astk.hasMoreTokens()){
           asa.add(astk.nextToken());
        }
    System.out.println(asa);
}

}

Outputs

[46.102.241.199, 3128]

You can now access the elements in an ArrayList. The first index holds the IP while the second holds the port.

Upvotes: 2

Marcus
Marcus

Reputation: 12586

This regex would get you an IP with an optional port. If there's always a port remove the questionmark at the end of the line.

\d{1,3}(?:\.\d{1,3}){3}(?::\d{1,5})?

Note that this is a simplified validation of an IPv4 and will only match that they are one the correct format and not a valid one. And remember to add an extra backslash to escape each backslash in java.

Here's an example in java:

String text = "46.102.241.199:3128 0.2990 Transp. NN N 100% 2011-11-19 17:56:02";
String pattern = "\\d{1,3}(?:\\.\\d{1,3}){3}(?::\\d{1,5})?";

Pattern compiledPattern = Pattern.compile(pattern);
Matcher matcher = compiledPattern.matcher(text);
while (matcher.find()) {
    System.out.println(matcher.group());
}

Output:

46.102.241.199:3128

Upvotes: 7

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