CODEWITHSUNDEEP
file
user533507
user533507

Reputation:

Shell script - Search through all files?

I am trying to write a shell script that will search for a file name (given as an argument) and if the file was modified less than or equal to 10 minutes ago, exit 0, if it was modified more than 10 minutes ago exit 1, and if the file doesn't exist exit 2.

Here's my code: 

if find $1
then
        if find $1 -mmin -11
        then
                echo "Exit 0"
        else
                echo "Exit 1"
        fi
else
        echo "Exit 2"
fi

How do I make this search through ALL files on the system?

Also, if the file exists then check if it was modified within the past 10 minutes, if it was then exit 1. If the file doesn't exist then exit 2. I have used echo "" so that I can see which exit happens.

Upvotes: 2

Views: 310

Answers (2)

William Pursell
William Pursell

Reputation: 212654

What do you want to do if there are two files of that name found on the filesystem? (For the moment, I'll assume that is not an issue and only work with the first file found.) Your question contradicts itself: in the preamble you say you want to exit with 0 if it has been modified in the last 10 minutes, but later you say that a recent modification should trigger an exit of 1. The following solution returns 0 of the file has NOT been modified in the last 10 minutes. This requires the gnu extension to date that gives the %s format specifier.

#!/bin/sh

fullpath=$( find / -name ${1?No file specified} | sed 1q | grep . ) || exit 2
test $( expr $( date +%s ) - $( stat -c %Y $fullpath )) -gt 600

Upvotes: 0

lukecampbell
lukecampbell

Reputation: 15266

if [[ -n $1 ]]; then 
  find / -name $1 -mmtime -10 2>/dev/null
  if [[ $? == 0 ]]; then 
    exit 0
  else
    exit 1
  fi
else
 ...

Upvotes: 1

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