CODEWITHSUNDEEP
pythonif-statement
eikonal
eikonal

Reputation: 171

number in a given range if loop python

I'm trying to compute this simple expression in python:

if a number is bigger than -1.0 and smaller than 1.0 do something.

I tried this:

if x > '-1.0' and x < '1.0':
    DoSomething

but it turns out that it evaluates only the second part (x < '1.0'). I also tried

if '-1.0' < x < '1.0':
    DoSomething

but strangely I don't get what I want. Any suggestion please????

Upvotes: 3

Views: 15793

Answers (5)

user2264607
user2264607

Reputation: 11

This will also work:

if abs(x) < 1.0

Upvotes: 1

Andrew Clark
Andrew Clark

Reputation: 208425

As other answers have mentioned, you need to remove the quotes so that you are comparing with numbers rather than strings.

However, none of those answers used Python's chained comparisons:

if -1.0 < x < 1.0:
    DoSomething

This is equivalent to if x > -1.0 and x < 1.0, but more efficient because x is only evaluated once.

Upvotes: 2

Jon Rubins
Jon Rubins

Reputation: 4413

What you are doing in that code is comparing x with the string value '-1.0' or '1.0', not the double value. Try the following:

if x > -1.0 and x < 1.0:

Upvotes: 1

srgerg
srgerg

Reputation: 19329

You don't want to put the numbers in quotes - that results in a string comparison, not a numeric comparison. You want

if x > -1.0 and x < 1.0:
    DoSomething

Upvotes: 2

Matthew Iselin
Matthew Iselin

Reputation: 10670

You are comparing with strings, not numbers.

if x > -1.0 and x < 1.0:
    pass

Will do the comparison on numbers.

Upvotes: 8

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