CODEWITHSUNDEEP
symfony1symfony-1.4
Patrick
Patrick

Reputation: 335

Symfony 1.4: How to change a submit input button into an HTML link

Seems like a simple thing, but I'm having a hell of time doing it.

I'm sure it's a quick fix... any help would be appreciated.

Here's the code:

<!-- apps/frontend/modules/job/templates/_form.php -->
<?php use_stylesheets_for_form($form) ?>
<?php use_javascripts_for_form($form) ?>

<?php echo form_tag_for($form, '@job') ?>
  <table id="job_form">
    <tfoot>
      <tr>
        <td colspan="2">
          <input type="submit" value="Preview your job" />
        </td>
      </tr>
    </tfoot>
    <tbody>
      <?php echo $form ?>
    </tbody>
  </table>
</form>

Yes, this is straight from the JObeet tutorial... found here: http://www.symfony-project.org/jobeet/1_4/Propel/en/10

With all the helpers, I thought this may be a symfony issue. Apparently not? At any rate, there is no action attributed to this post input method, so I can't use link_to or url_for helpers.

Upvotes: 1

Views: 2371

Answers (1)

Manse
Manse

Reputation: 38137

Firstly update your form_tag_for function call to include some attributes and give the form an id :

<?php echo form_tag_for($form, '@job', array('id' => 'the_form')) ?>

Then replace your submit button with something like this :

<a href="javascript:{}" onclick="document.getElementById('the_form').submit(); return false;">Submit</a>

As @domi27 suggested - The symfony way - ie using helpers is the following :

<?php echo link_to_function('Submit', "document.getElementById('the_form').submit()") ?>

Upvotes: 2

Related Questions