Reputation: 380
I have several independant int variables in my program. Is there a way I can feed randomly the value of one of them into a new int variable or an int array ? Thanks in Advance.
EDIT:
here's a pseudocode to demonstrate:
int A1 = 1;
int A2 = 3;
int RESULT = 0;
Random rand = new Random();
Result = rand.Next(0, A1 || A2)]; //Result holds the value/variable name of A1 or A2
Upvotes: 1
Views: 3070
Reputation: 61
I had some trouble myself and found this thread, but its code is for Ints only, so I was stuck for some time to make it work for other than ints. I think @David gave me some idea how to make it work. This is my version for using types other than ints.
Vector2 down = new Vector2(0, 1);
Vector2 left = new Vector2(-1, 0);
Vector2 right = new Vector2(1, 0);
List<Vector2> possibleDirections = new List<Vector2>()
{
down,
left,
right
};
Random random = new Random();
Vector2 selectedRandomDirection = possibleDirections[random.Next(0, possibleDirections.Count)];
// this is the result
Vector2 direction = selectedRandomDirection;
Upvotes: 0
Reputation: 3965
How about this:
// create an array of your variables
int[] A = new int[] {1,3};
// Instantiate Random object.
Random rand = new Random();
// Get a value between 0 and the lenght of your array.
// This is equivalent to select one of the elements of the array.
int index = rand.Next(0,A.Length);
// Get the value from the array that was selected at random.
int Result = A[index];
Upvotes: 0
Reputation: 209
You could put all the ints you want to choose from in a new array and then select a random value from it. For example:
int value1 = 3;
int anotherValue = 5;
int value2 = 1;
int[] selectableInts = new int[3] { value1, anotherValue, value2 };
Random rand = new Random();
int randomValue = selectableInts[rand.Next(0, selectableInts.Length)];
Upvotes: 3