Reputation: 310
When I run the following SQL query in my Oracle database:
SELECT p.pkt_nazwa,
u.us_nazwa
FROM punkty p,
kategorie_uslug ku,
usluga u
WHERE ku.pkt_id = p.pktk_1_id
AND ku.us_id = u.usk_1_id
ORDER BY p.pkt_nazwa;
I get the following output:
NAME | SERVICE
--------------------|-------------------
Baita De Mario | WC
Baita De Mario | Kuchnia
Baita De Mario | Nocleg
Bistro-Cafe | Bar
Bistro-Cafe | Dyskoteka
Bistro-Cafe | Kuchnia
How would I go about to get the following output?
NAME | SERVICES
--------------------|-------------------
Baita De Mario | WC, Kuchnia, Nocleg
Bistro-Cafe | Bar, Dyskoteka, Kuchnia
Upvotes: 1
Views: 189
Reputation:
Since Oracle 11.2 this has become easier using listagg()
SELECT p.pkt_nazwa AS name,
listagg(u.us_nazwa) WITHIN GROUP (ORDER BY u.us_nazwa) AS services
FROM punkty p
JOIN kategorie_uslug ku ON ku.pkt_id = p.pktk_1_id
JOIN usluga u ON u.usk_1_id = ku.us_id
GROUP BY p.pkt_nazwa
ORDER BY p.pkt_nazwa;
Upvotes: 0
Reputation: 656521
SELECT p.pkt_nazwa AS name, wm_concat(u.us_nazwa) AS services
FROM punkty p
JOIN kategorie_uslug ku ON ku.pkt_id = p.pktk_1_id
JOIN usluga u ON u.usk_1_id = ku.us_id
GROUP BY p.pkt_nazwa
ORDER BY p.pkt_nazwa;
wm_concat() function is present in most versions.
More about string aggregating in Oracle.
Upvotes: 3
Reputation: 2476
Here's an article explaining some approaches to what you're trying to do in Oracle:
http://www.oracle-base.com/articles/misc/StringAggregationTechniques.php
Note that if you're running 11g Release 2 then LISTAGG is the way to go.
Upvotes: 3