Reputation: 8528
I'm looking for a std::ostream
implementation that acts like /dev/null
. It would just ignore anything that is streamed to it. Does such a thing exist in the standard libraries or Boost? Or do I have to roll my own?
Upvotes: 71
Views: 35879
Reputation: 550
Following the @user5406764's answer, it is possible to skip any actual operations by overloading the global <<
operator. The solution should be cross-platform and the fastest one.
#include <iostream>
class NullStream : public std::ostream {
public:
NullStream() : std::ostream(nullptr) {}
NullStream(const NullStream &) : std::ostream(nullptr) {}
};
template <class T>
NullStream &operator<<(NullStream &os, const T &value) {
return os;
}
NullStream null;
int main() {
std::cerr << "a" << std::endl;
null << "b" << std::endl;
std::cerr << "c" << std::endl;
}
Output:
a
c
Upvotes: 6
Reputation: 11555
You can do it without third-party libraries. Just set the associated stream buffer to nullptr
using rdbuf
and your job is done
std::cout << "Hello,";
std::cout.rdbuf(nullptr);
std::cout << " world!\n";
Online example here.
Upvotes: 3
Reputation: 1795
struct NullStream // only subclass std::stream if you must
{
template<typename T>
NullStream& operator<<(T const&) { return *this; }
};
NullStream TheNullStream; // There's your global instance
Upvotes: 1
Reputation: 11
May this solution overcomes the performance issue without using boost:
#include <ostream>
class dev0_buffer : public std::streambuf
{
//called usually for n-characters
std::streamsize xsputn (const char* s, std::streamsize n) override { return n; }
//may not required due it's not called anymore
int overflow (int c) override { return c; }
} nirwana;
class dev0_stream : public std::ostream
{
public:
dev0_stream(): std::ostream(&nirwana){}
};
Upvotes: 0
Reputation: 9
As for me the simplest way would be:
#include <fstream>
std::ostream* out = &std::cout;
std::ostream* nullstream() {
static std::ofstream os;
if (!os.is_open())
os.open("/dev/null", std::ofstream::out | std::ofstream::app);
return &os;
}
int main() {
*out << "Normal output\n";
out = nullstream();
*out << "Will not visible\n";
out = &std::cout;
*out << "Back again\n";
return 0;
}
Or use 'badbit' flag instead of '/dev/null' in 'nullstream' function as described above.
std::ostream* nullstream() {
static std::ofstream os;
static bool flag_set = false;
if (!flag_set) {
os.setstate(std::ios_base::badbit);
flag_set = true;
}
return &os;
}
Upvotes: 0
Reputation: 3335
I know this is very old thread, but I would like to add this to anyone who is looking for the same solution without boost and the fastest one.
I combined three different proposals above and one writing directly to /dev/null (so it involves kernel.)
Surprisingly the NullStream that got the most votes performed the worst.
Here are results for 100,000,000 writes:
a) /dev/null : 30 seconds
b) NullStream: 50 seconds
c) badbit : 16 seconds (the winner in speed, but cannot test for errors!)
d) boost : 25 seconds (the ultimate winner)
Here is the test code
#include <iostream>
#include <fstream>
#include <time.h>
#include <boost/iostreams/stream.hpp>
class NullStream : public std::ostream {
class NullBuffer : public std::streambuf {
public:
int overflow( int c ) { return c; }
} m_nb;
public:
NullStream() : std::ostream( &m_nb ) {}
};
int test( std::ostream& ofs, const char* who ) {
const time_t t = time(NULL);
for ( int i = 0 ; i < 1000000000 ; i++ )
ofs << "Say the same" ;
std::cout << who << ": " << time(NULL) - t << std::endl;
}
void devnull() {
std::ofstream ofs;
ofs.open( "/dev/null", std::ofstream::out | std::ofstream::app );
test(ofs, __FUNCTION__);
ofs.close();
}
void nullstream() {
NullStream ofs;
test(ofs, __FUNCTION__);
}
void badbit() {
std::ofstream ofs;
ofs.setstate(std::ios_base::badbit);
test(ofs, __FUNCTION__);
}
void boostnull() {
boost::iostreams::stream< boost::iostreams::null_sink > nullOstream( ( boost::iostreams::null_sink() ) );
test(nullOstream, __FUNCTION__);
}
int main() {
devnull();
nullstream();
badbit();
boostnull();
return 0;
}
EDIT
The fastest solution - where we use badbit - has a downside. If the program checks if the output is successfully written - and I have no idea why the program should not do that - then it will fail because of this badbit. Therefore, the runner up - boost - is the winner.
Upvotes: 25
Reputation: 153977
The simplest solution is just to use an unopened std::ofstream
. This
will result in an error state in the stream, but most outputters won't
check this; the usual idiom is to leave the check to the end, after the
close (which would put it in code you wrote, where you know that the
stream should be invalid).
Otherwise, it's pretty straight forward to implement: just create a
streambuf
which contains a small buffer, and sets it up in overflow
(always returning success). Note that this will be slower than the
unopened file, however; the various >>
operators will still to all of
the conversion (which they don't do if the stream has an error state).
EDIT:
class NulStreambuf : public std::streambuf
{
char dummyBuffer[ 64 ];
protected:
virtual int overflow( int c )
{
setp( dummyBuffer, dummyBuffer + sizeof( dummyBuffer ) );
return (c == traits_type::eof()) ? '\0' : c;
}
};
It's usual to provide a convenience class derived from istream
or ostream
as well, which will contain an instance of this
buffer which it uses. Something along the lines of:
class NulOStream : private NulStreambuf, public std::ostream
{
public:
NulOStream() : std::ostream( this ) {}
NulStreambuf* rdbuf() const { return this; }
};
Or you can just use an std::ostream
, passing the address of
the streambuf to it.
Upvotes: 28
Reputation: 4291
If you have boost, then there's a null ostream & istream implementation available in boost/iostreams/device/null.hpp . The gist of it:
#include "boost/iostreams/stream.hpp"
#include "boost/iostreams/device/null.hpp"
...
boost::iostreams::stream< boost::iostreams::null_sink > nullOstream( ( boost::iostreams::null_sink() ) );
...
Upvotes: 30
Reputation: 136425
If you set badbit
on a stream it won't output anything:
#include <iostream>
int main() {
std::cout << "a\n";
std::cout.setstate(std::ios_base::badbit);
std::cout << "b\n";
std::cout.clear();
std::cout << "c\n";
}
Outputs:
a
c
Upvotes: 22