CODEWITHSUNDEEP
c#xml
Ayush
Ayush

Reputation: 42450

How would I parse this XML String?

I have an XML string like this:

<Summary>Foo</Summary><Description>Bar</Description>

I want to read this into a class object:

class Foobar()
{
    string Summary {get;set;}
    string Description {get;set;}
}

I tried using XmlTextReader, but it throws an exception that no root element was found. This is what I tried:

using (XmlTextReader reader = new XmlTextReader(new StringReader(comment)))
{
     while (reader.Read())
     //do something here
}

I also tried deserializing it directly into an object like this:

[XmlTypeAttribute]    
    public class Foobar
    {

        [XmlElementAttribute("Summary")]
        public string Summary { get; set; }

        [XmlElementAttribute("Description")]
        public string Description { get; set; }        

    }

This fails as well because I cannot define a [XmlRootElement] for the class Foobar, since there is no root element.

Upvotes: 2

Views: 104

Answers (4)

Jon Hanna
Jon Hanna

Reputation: 113352

Use a constructor form that allows for XMLFragments (chunks of XML that could be valid if put into a single element, but which are not so-rooted):

using (XmlTextReader reader = new XmlTextReader(comment, XmlNodeType.Element, null))
{
     while (reader.Read())
     //do something here
}

Better yet, use Create(), which gives more flexibility still.

Upvotes: 0

Kevin Gosse
Kevin Gosse

Reputation: 39017

The easiest way is probably to manually add a root element.

string xml = "<root>" + comment + "</root>";

Then you can parse it with whichever method you want.

Upvotes: 1

Pankaj Upadhyay
Pankaj Upadhyay

Reputation: 13594

Define a root element

<root>
    <Summary>Foo</Summary>
    <Description>Bar</Desciption>
</root>

Upvotes: 3

Pranay Rana
Pranay Rana

Reputation: 176956

You need to set root element for that your xaml would be 

<root>
<Summary>Foo</Summary><Description>Bar</Description> 
</root>

For Rootelement in XMLSeralizatoion : http://msdn.microsoft.com/en-us/library/system.xml.serialization.xmlrootattribute.aspx

Upvotes: 3

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