Reputation: 1128
SELECT COUNT(*) as totalHappenings FROM `happenings` WHERE `userId` = ?
UNION
SELECT COUNT(*) as xHappenings FROM `happenings` WHERE `userId` = ? AND `destinationObjectType` = \'2\'
UNION
SELECT COUNT(*) as yHappenings FROM `happenings` WHERE `userId` = ? AND `destinationObjectType` = \'1\'
Since it's the same table, and I don't wanna pass through 3 times the userId parameter how can I solve this the best way?
Upvotes: 0
Views: 443
Reputation: 5894
SELECT
COUNT(*) AS totalHappenings,
SUM(CASE WHEN `destinationObjectType` = \'2\' THEN 1 ELSE 0 END) AS xHappenings,
SUM(CASE WHEN `destinationObjectType` = \'1\' THEN 1 ELSE 0 END) AS yHappenings
FROM `happendings`
WHERE `userId` = ?
Result:
totalHappenings xHappenings yHappenings
24 10 14
Upvotes: 2
Reputation: 7722
try the shortest way:
SELECT COUNT(*) as totalHappenings, SUM(`destinationObjectType` = \'2\') AS xHappenings, SUM(`destinationObjectType` = \'1\') AS yHappenings FROM `happenings` WHERE `userId` = ?
comparision inside SUM
returns true or false (1 or 0) so there is no need for IF
or CASE
statements
Upvotes: 0
Reputation: 4599
You can do this with if statements inside select clause:
SELECT
COUNT(userId) as totalHappenings,
SUM(IF(`destinationObjectType`='2',1,0) as xHappenings,
SUM(IF(`destinationObjectType`='1',1,0) as yHappenings
FROM `happenings`
WHERE `userId` = ?
This will surely return your results in 3 columns. Your original query was returning in 3 rows but I think that is not a problem.
Upvotes: 1