Reputation: 2397
I have the next table:
+---------+------------+
| firm_id | service_id |
+---------+------------+
| 6 | 2 |
| 6 | 4 |
| 23 | 7 |
| 23 | 6 |
I want to get ONLY companies who do not have service_id=4 in their service list.
A query of the above table should return only the company with firm_id=23 because firm_id=6 has one record with service_id=4.
I want to make it with one query. Is this possible (without joins)?
Thanks.
P.S. Thanks everyone. User "derobert" suggested very interesting way, what i was looking for.
Upvotes: 1
Views: 293
Reputation: 51157
You can do it several ways. Here is one, with a correlated subquery:
SELECT DISTINCT firm_id FROM table t1
WHERE NOT EXISTS ( SELECT 1 FROM table t2 WHERE t1.firm_id = t2.firm_id AND t2.service_id = 4)
In MySQL-land it is often better to rewrite as a self-join:
SELECT DISTINCT firm_id
FROM table t1 LEFT JOIN table t2 ON (t1.firm_id = t2.firm_id AND t2.service_id = 4)
WHERE t2.firm_id IS NULL
Finally, here is one way to do it that doesn't involve subqueries or joins (but I expect performs worse than either of the above)
SELECT firm_id, CONCAT(',', GROUP_CONCAT(service_id SEPARATOR ','), ',') AS service_ids
FROM table t1
GROUP BY firm_id
HAVING service_ids NOT LIKE '%,4,%'
I confess I haven't actually run these; please forgive typos.
Upvotes: 5
Reputation: 57583
You could try
SELECT * FROM your_table
WHERE firm_id NOT IN
(SELECT DISTINCT firm_id FROM your_table
WHERE service_id = 4) a
As suggested by ypercube (thanks!) you can also try
SELECT DISTINCT firm_id, service_id FROM your_table
WHERE firm_id NOT IN
(SELECT firm_id FROM your_table
WHERE service_id = 4) a
Upvotes: 1
Reputation: 115590
SELECT DISTINCT
firm_id
FROM
TableX AS t
WHERE
NOT EXISTS
( SELECT
*
FROM
TableX AS s
WHERE
s.firm_id = t.firm_id
AND
s.service_id = 4
)
or:
SELECT
firm_id
FROM
TableX
GROUP BY
firm_id
HAVING
COUNT(service_id = 4) = 0
Upvotes: 3