Reputation: 91999
I am trying to do the following :
def get_collection_iterator(collection_name, find={}, criteria=None):
collection = db[collection_name]
# prepare the list of values of collection
if collection is None:
logging.error('Mongo could not return the collecton - ' + collection_name)
return None
collection = collection.find(find, criteria)
for doc in collection:
yield doc
and calling like :
def get_collection():
criteria = {'unique_key': 0, '_id': 0}
for document in Mongo.get_collection_iterator('contract', {}, criteria):
print document
and I see the error saying :
File "/Users/Dev/Documents/work/dw/src/utilities/Mongo.py", line 96
yield doc
SyntaxError: 'return' with argument inside generator
what is that I am doing incorrect here?
Upvotes: 5
Views: 6161
Reputation: 49095
It seems the problem is that Python doesn't allow you to mix return
and yield
-- you use both within get_collection_iterator
.
Clarification (thanks to rob mayoff): return x
and yield
can't be mixed, but a bare return
can
Upvotes: 12
Reputation: 10257
Your problem is in the event None
must be returned, but it is detected as a syntax error since the return would break the iteration loop.
Generators that are intended to use yield
to handoff values in loops can't use return with argument values, as this would trigger a StopIteration
error. Rather than returning None
, you may want to raise an exception and catch it in the calling context.
http://www.answermysearches.com/python-fixing-syntaxerror-return-with-argument-inside-generator/354/
def get_collection_iterator(collection_name, find={}, criteria=None):
collection = db[collection_name]
# prepare the list of values of collection
if collection is None:
err_msg = 'Mongo could not return the collecton - ' + collection_name
logging.error(err_msg)
raise Exception(err_msg)
collection = collection.find(find, criteria)
for doc in collection:
yield doc
You could make a special exception for this too if need be.
Upvotes: 3