Reputation: 2285
So I understand how to remove duplicates in a list when it comes to strings and int, etc by using Distinct()
from Linq. But how do you remove duplicates based on a specific attribute of an object?
For example, I have a TimeMetric
class. This TimeMetric
class has two attributes: MetricText
and MetricTime
. I have a list of TimeMetrics
called MetricList
. I want to remove any duplicates TimeMetric
with the same MetricText
attribute. The TimeMetric
value can be the same but if any TimeMetric
has the same MetricText
, it must be unduplicated.
Upvotes: 18
Views: 23402
Reputation: 11699
You can use Distinct overload with an IEqualityComparer.
Your equals method for your IEqualityComparer implementation would look like this:
bool Equals(TimeMetric x, TimeMetric y)
{
return x.MetricText.Equals(y.MetricText);
}
Upvotes: 3
Reputation: 11598
Use linq:
var list = list
.GroupBy(i => i.MetricText)
.Select(g => g.First())
.ToList();
Or pass in a comparer that uses the property:
public class mtCompare : IEqualityComparer<TimeMetric>
{
public bool Equals(TimeMetric x, TimeMetric y)
{
return Equals(x.MetricText, y.MetricText);
}
public int GetHashCode(TimeMetric obj)
{
return obj.MetricText.GetHashCode();
}
}
....
list.Distinct(new mtCompare());
Upvotes: 15
Reputation: 437376
You need to use the second overload of Distinct
that takes an IEqualityComparer<TimeMetric>
instance as a second parameter. Define a comparer like this:
class MyComparer : IEqualityComparer<TimeMetric>
{
public bool Equals(TimeMetric x, TimeMetric y)
{
return x.MetricText.Equals(y.MetricText);
}
public int GetHashCode(TimeMetric obj)
{
return obj.MetricText.GetHashCode();
}
}
Important note: The above code does not check for the case where the MetricText
property is null
(and it sounds like it could be, since it's most probably a string
). You should do that and return 0
from GetHashCode
if MetricText
is null
. On the other hand, if the type of MetricText
is a value type, you don't need to perform any modification.
And then:
var list = new List<TimeMetric> { ... };
var unique = list.Distinct(new MyComparer());
Upvotes: 21