CODEWITHSUNDEEP
try-catch
Phi Tống
Phi Tống

Reputation: 11

PHP - How to keep program still run when have error

In the example code:

<?php
    for ($i = 1; $i <=20; $i++) {
        echo $i . '<br />';
        if ($i == 10) {
            $haha->hoho("hehe");
        }
    }
?>

When $i = 10 program will show this error, Call to a member function hoho() on a non-object because $haha is not a object and the program stops running. I want the program to handle this error and continue running to $i=20. How can I do it?

Upvotes: 1

Views: 101

Answers (2)

user529649
user529649

Reputation:

The Simple answer: Fix your code.

Long answer:

There is lots of ways to do that, the first thing off the top of my head is to use set_error_handler() regardless of your programming pattern.

But if you are doing it in OOP you should make use of magic methods(what?) like __call and __get -obviously the $haha needs to be the object in your example.

Hint: Using Exception in magic methods is really good idea. but you can't handle this directly with exception because Internal PHP functions mainly use Error reporting, only modern Object oriented extensions use exceptions.

Upvotes: 1

Mike Lentini
Mike Lentini

Reputation: 1358

I would try something like:

<?php
    for ($i = 1; $i <=20; $i++) {
        echo $i . '<br />';
        if ($i == 10) {
            if ($haha) $haha->hoho("hehe");
        }
    }
?>

This should check if $haha exists before it tries to do $haha->hoho("hehe");

Upvotes: 0

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