Reputation: 273
The error is at location http://127.0.0.1:8000/fileupload/form.py
I have version 1.3 of django. I have tried specifying localhost:8000 as stated in someone else's question but this did not work for me. I am trying to have a file upload form but I am receiving an error that form.py does not have the CSRF token.
form.py:
class UploadFileForm(forms.Form):
title = forms.CharField(max_length=50)
file = forms.FileField()
views.py:
def upload_file(request):
c = {}
c.update(csrf(request))
if (not request.user.is_authenticated()) or (request.user == None):
return HttpResponseRedirect("/?error=11")
if request.method == 'POST':
form = c['UploadFileForm'] = UploadFileForm(request.POST, request.FILES, c, context_instance=RequestContext(request))
if c['UploadFileForm'].is_valid():
handle_uploaded_file(request.FILES['file'])
return HttpResponseRedirect('/success/url/')
else:
form = c['UploadFileForm'] = UploadFileForm()
return render_to_response('fileupload/upload.html', {'form': c['UploadFileForm']})
upload.html:
{% block main_content %}
<form action="fileupload/form.py" enctype="multipart/form-data" method="POST">
{% csrf_token %}
<table>
<tr><td>Title:</td><td><input type="text" name="title" /></td></tr>
<tr><td>File:</td><td><input type="file" name="file" /></td></tr>
</table>
<input type="submit" value="Submit" class = "float_right button_input" />
</form>
{% endblock main_content %}
I am very stumped please tell me some things to try. Thank You
Upvotes: 27
Views: 124252
Reputation: 17
For my case, I use AJAX to post data to my views function, then the same error happens, so the easy method to solve it is to change the data from
data:{ 'k':'v' }
To
data:{ 'k':'v' ,addcsrfmiddlewaretoken:'{{ csrf_token }}',}
because we manually add a csrf-token, so it is not missing or incorrect.
Upvotes: 1
Reputation: 14731
It can also happen if you use @cache_page(60 * 15)
decorators. If you cache a page with a form containing a CSRF token, you'll cache the CSRF token of the first user only. So it's kinda hard to debug sometimes.
More info from Django documentation
If the csrf_token template tag is used by a template (or the get_token function is called some other way), CsrfViewMiddleware will add a cookie and a Vary: Cookie header to the response. This means that the middleware will play well with the cache middleware if it is used as instructed (UpdateCacheMiddleware goes before all other middleware).
However, if you use cache decorators on individual views, the CSRF middleware will not yet have been able to set the Vary header or the CSRF cookie, and the response will be cached without either one. In this case, on any views that will require a CSRF token to be inserted you should use the django.views.decorators.csrf.csrf_protect() decorator first:
from django.views.decorators.cache import cache_page from django.views.decorators.csrf import csrf_protect @cache_page(60 * 15) @csrf_protect def my_view(request): ...
Upvotes: 6
Reputation: 393
My answer is similar to the @Yugal Jindle's answer above.
I am using Django 1.10 and I had a similar issue, it worked for me after editing
return render_to_response(param1, param2)
to
return render(request, param1, param2)
P.S. Make sure you have the below line in your MIDDLEWARE variable in the settings.py
'django.middleware.csrf.CsrfViewMiddleware'
Upvotes: 2
Reputation: 45696
You need to pass RequestContext
in render_to_response for csrf_token
For this : (views.py)
from django.template import RequestContext
...
return render_to_response('fileupload/upload.html', {'form': c['UploadFileForm']}, RequestContext(request))
# Added RequestContext
This passes the token for csrf to the template.
Upvotes: 42