CODEWITHSUNDEEP
algorithmgeometry2dgisconcave-hull
Fabio Ceconello
Fabio Ceconello

Reputation: 16039

Is there an efficient algorithm to generate a 2D concave hull?

Having a set of (2D) points from a GIS file (a city map), I need to generate the polygon that defines the 'contour' for that map (its boundary). Its input parameters would be the points set and a 'maximum edge length'. It would then output the corresponding (probably non-convex) polygon.

The best solution I found so far was to generate the Delaunay triangles and then remove the external edges that are longer than the maximum edge length. After all the external edges are shorter than that, I simply remove the internal edges and get the polygon I want. The problem is, this is very time-consuming and I'm wondering if there's a better way.

Upvotes: 68

Views: 40471

Answers (10)

Jaybird64
Jaybird64

Reputation: 19

The Bing Maps V8 interactive SDK has a concave hull option within the advanced shape operations.

https://www.bing.com/mapspreview/sdkrelease/mapcontrol/isdk/advancedshapeoperations?toWww=1&redig=D53FACBB1A00423195C53D841EA0D14E#JS

Within ArcGIS 10.5.1, the 3D Analyst extension has a Minimum Bounding Volume tool with the geometry types of concave hull, sphere, envelope, or convex hull. It can be used at any license level.

There is a concave hull algorithm here: https://github.com/mapbox/concaveman

Upvotes: 1

Evan Carroll
Evan Carroll

Reputation: 1

As a wildly adopted reference, PostGIS starts with a convexhull and then caves it in, you can see it here.

https://github.com/postgis/postgis/blob/380583da73227ca1a52da0e0b3413b92ae69af9d/postgis/postgis.sql.in#L5819

Upvotes: 1

Cameron
Cameron

Reputation: 169

You can do it in QGIS with this plug in; https://github.com/detlevn/QGIS-ConcaveHull-Plugin

Depending on how you need it to interact with your data, probably worth checking out how it was done here.

Upvotes: 1

Amirali
Amirali

Reputation: 126

This paper discusses the Efficient generation of simple polygons for characterizing the shape of a set of points in the plane and provides the algorithm. There's also a Java applet utilizing the same algorithm here.

Upvotes: 5

Rob Dickerson
Rob Dickerson

Reputation: 1469

Good question! I haven't tried this out at all, but my first shot would be this iterative method:

  1. Create a set N ("not contained"), and add all points in your set to N.
  2. Pick 3 points from N at random to form an initial polygon P. Remove them from N.
  3. Use some point-in-polygon algorithm and look at points in N. For each point in N, if it is now contained by P, remove it from N. As soon as you find a point in N that is still not contained in P, continue to step 4. If N becomes empty, you're done.
  4. Call the point you found A. Find the line in P closest to A, and add A in the middle of it.
  5. Go back to step 3

I think it would work as long as it performs well enough — a good heuristic for your initial 3 points might help.

Good luck!

Upvotes: 1

monnoo
monnoo

Reputation: 311

The answer may still be interesting for somebody else: One may apply a variation of the marching square algorithm, applied (1) within the concave hull, and (2) then on (e.g. 3) different scales that my depend on the average density of points. The scales need to be int multiples of each other, such you build a grid you can use for efficient sampling. This allows to quickly find empty samples=squares, samples that are completely within a "cluster/cloud" of points, and those, which are in between. The latter category then can be used to determine easily the poly-line that represents a part of the concave hull.

Everything is linear in this approach, no triangulation is needed, it does not use alpha shapes and it is different from the commercial/patented offering as described here ( http://www.concavehull.com/ )

Upvotes: 2

Mike F
Mike F

Reputation:

A simple solution is to walk around the edge of the polygon. Given a current edge om the boundary connecting points P0 and P1, the next point on the boundary P2 will be the point with the smallest possible A, where

H01 = bearing from P0 to P1
H12 = bearing from P1 to P2
A = fmod( H12-H01+360, 360 )
|P2-P1| <= MaxEdgeLength

Then you set

P0 <- P1
P1 <- P2

and repeat until you get back where you started.

This is still O(N^2) so you'll want to sort your pointlist a little. You can limit the set of points you need to consider at each iteration if you sort points on, say, their bearing from the city's centroid.

Upvotes: 1

Vinko Vrsalovic
Vinko Vrsalovic

Reputation: 340151

The guys here claim to have developed a k nearest neighbors approach to determining the concave hull of a set of points which behaves "almost linearly on the number of points". Sadly their paper seems to be very well guarded and you'll have to ask them for it.

Here's a good set of references that includes the above and might lead you to find a better approach.

Upvotes: 3

Martin Beckett
Martin Beckett

Reputation: 96119

A quick approximate solution (also useful for convex hulls) is to find the north and south bounds for each small element east-west.

Based on how much detail you want, create a fixed sized array of upper/lower bounds. For each point calculate which E-W column it is in and then update the upper/lower bounds for that column. After you processed all the points you can interpolate the upper/lower points for those columns that missed.

It's also worth doing a quick check beforehand for very long thin shapes and deciding wether to bin NS or Ew.

Upvotes: 1

nsanders
nsanders

Reputation: 12626

One of the former students in our lab used some applicable techniques for his PhD thesis. I believe one of them is called "alpha shapes" and is referenced in the following paper:

http://www.cis.rit.edu/people/faculty/kerekes/pdfs/AIPR_2007_Gurram.pdf

That paper gives some further references you can follow.

Upvotes: 12

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