Reputation: 131
I understand you can pass a function as an argument to another function like so
var fn = function(){alert('Hello')}
function outer(a,fn){
fn();
}
How can you pass an anonymous function to another function and have it invoked within the function after taking a parameter from the outer function?
function outer(function(x){alert(x);})
{
var xVar = "foo";
//..would liked to pass xVar to the anaonymous function
//passed as a param to the function so that "foo" is displayed as message...
}
Please note changing the signature of outer would be the last choice.
Upvotes: 0
Views: 311
Reputation: 359826
You're confusing function invocation (calling a function) with function declaration (defining a function). Here's how do what you ask:
// declare the outer function
function outer(func)
{
var xVar = 'foo';
func(xVar)
}
// now invoke it
outer(function (x)
{
alert(x);
});
Upvotes: 1