Reputation: 19636
I made an anagram machine and I have an array of positive matches. The trouble is they are all in a different order, I want to be able to sort the array so the longest array values appear first.
Anybody have any ideas on how to do this?
Upvotes: 70
Views: 77905
Reputation: 46781
Use https://www.php.net/manual/en/function.usort.php
with this custom function
function sortByLength($a,$b){
return strlen($b)-strlen($a);
}
usort($array,'sortByLength');
Use uasort if you want to keep the old indexes, use usort if you don't care.
Also, I believe that my version is better because usort is an unstable sort.
$array = array("bbbbb", "dog", "cat", "aaa", "aaaa");
// mine
[0] => bbbbb
[1] => aaaa
[2] => aaa
[3] => cat
[4] => dog
// others
[0] => bbbbb
[1] => aaaa
[2] => dog
[3] => aaa
[4] => cat
Upvotes: 165
Reputation: 47904
Here is a snippet that demonstrates exactly why you should NOT use function calls inside of usort()
-- you will be needlessly calling strlen()
on values that were previously encountered.
In my 9-element array, array_multisort()
calls strlen()
9 times, but usort()
calls strlen()
23 times -- that's no bueno.
Code: (Demo)
function multisort($array) {
array_multisort(array_map('strlen', $array), SORT_DESC, $array);
printf(
"Total strlen() calls: %d\n%s\n---\n",
count($array),
var_export($array, true)
);
}
function usersort($array) {
usort(
$array,
function($a, $b) {
echo "strlen() called twice\n";
return strlen($b) <=> strlen($a);
}
);
var_export($array);
echo "\n---\n";
}
multisort($array);
usersort($array);
Output (from my own sample array):
Total strlen() calls: 9
array (
0 => 'eight',
1 => 'seven',
2 => 'three',
3 => 'five',
4 => 'four',
5 => 'nine',
6 => 'one',
7 => 'six',
8 => 'two',
)
---
strlen() called twice
strlen() called twice
strlen() called twice
strlen() called twice
strlen() called twice
strlen() called twice
strlen() called twice
strlen() called twice
strlen() called twice
strlen() called twice
strlen() called twice
strlen() called twice
strlen() called twice
strlen() called twice
strlen() called twice
strlen() called twice
strlen() called twice
strlen() called twice
strlen() called twice
strlen() called twice
strlen() called twice
strlen() called twice
strlen() called twice
array (
0 => 'three',
1 => 'seven',
2 => 'eight',
3 => 'four',
4 => 'five',
5 => 'nine',
6 => 'one',
7 => 'two',
8 => 'six',
)
---
Upvotes: 1
Reputation: 51
Descending Order:
$array = ['aa', 'bb', 'c', 'ccc', 'a', 'ertre'];
usort($array, function($a, $b){
return strlen($a) < strlen($b);
});
var_export($array);
// Output
array (
0 => 'ertre',
1 => 'ccc',
2 => 'aa',
3 => 'bb',
4 => 'c',
5 => 'a',
)
Ascending Order:
$array = ['aa', 'bb', 'c', 'ccc', 'a', 'ertre'];
usort($array, function($a, $b){
return strlen($a) > strlen($b);
});
// Output
array (
0 => 'c',
1 => 'a',
2 => 'aa',
3 => 'bb',
4 => 'ccc',
5 => 'ertre',
)
Upvotes: 5
Reputation: 149
Here's a way using the spaceship operator (needs PHP 7.0):
$arr = ['apple','pear','oranges','banana'];
usort($arr, function ($a, $b) { return (strlen($a) <=> strlen($b)); });
print_r($arr);
Upvotes: 0
Reputation: 551
PHP7 is coming. In PHP7, you could use the Spaceship Operator.
usort($array, function($a, $b) {
return strlen($b) <=> strlen($a);
});
Hope this could help you in the future.
Upvotes: 47
Reputation: 17205
In addition to the accepted answer, to sort an array by length with ascending OR descending order:
function strlen_compare($a,$b){
if(function_exists('mb_strlen')){
return mb_strlen($b) - mb_strlen($a);
}
else{
return strlen($b) - strlen($a);
}
}
function strlen_array_sort($array,$order='dsc'){
usort($array,'strlen_compare');
if($order=='asc'){
$array=array_reverse($array);
}
return $array;
}
Upvotes: 0
Reputation: 9
Make an array of strlen
of oyur array elements, and multisort
it with your array.
foreach($Yourarray as $c=>$key) {
$key['maxlen'] = strlen($key);
$sort_numcie[] = $key['maxlen'];
}
array_multisort($sort_numcie, $Yourarray);
This will definately work. I am sure!
Upvotes: 0
Reputation: 1158
If you'd like to do it the PHP 5.3 way, you might want to create something like this:
usort($array, function($a, $b) {
return strlen($b) - strlen($a);
});
This way you won't pollute your global namespace.
But do this only if you need it at a single place in your source code to keep things DRY.
Upvotes: 65
Reputation: 1
It's simple.
function LSort(a,b){return a.length-b.length;}
var YourArray=[[1,2,3,4,5,6], ['a','b'], ['X','Y','Z'], ['I','Love','You'], ['good man']];
YourArray.sort(Lsort);
Result:
['good man'] Length=1
['a','b'] Length=3
['X','Y','Z'] Length=3
['I','Love','You'] Length=3
[1,2,3,4,5,6] Length=6
Upvotes: -8
Reputation: 4366
Here's a way I've done it in the past.
// Here's the sorting...
$array = array_combine($words, array_map('strlen', $words));
arsort($array);
Upvotes: -1
Reputation: 10311
function sortByLength($a,$b){
if($a == $b) return 0;
return (strlen($a) > strlen($b) ? -1 : 1);
}
usort($array,'sortByLength');
Upvotes: 10