CODEWITHSUNDEEP
matlabsignal-processing
rjs
rjs

Reputation: 437

Applying derivative operation on Signal in Matlab

I've been given the formula below to apply to a signal. I'm not sure how to plug this into Matlab, can anyone explain?

y(n) =1/8[2x(n) + x(n − 1) − x(n − 3) − 2x(n − 4)]

Upvotes: 2

Views: 1879

Answers (1)

mtrw
mtrw

Reputation: 35088

If x is your input signal and y is your output, the expression you have can be regarded as an FIR filter. You can write the coefficients of x in a vector as b = (1/8)*[2, 1, 0, -1, -2]; (the 0 in the middle is the coefficient of x(n-2)). Then you can apply it to your input data vector x using the filter function: y = filter(b, 1, x); (the 1 in the middle represents the coefficient of y(n)).

It may also be of interest to see the frequency response of the filter. To do so, you can use the freqz command: freqz(b,1);. See the documentation for more details, including how to calibrate the x-axis of the plot in Hz. Use of this function requires the Signal Processing Toolbox from the Mathworks.

Upvotes: 4

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