CODEWITHSUNDEEP
phpapipostcurl
ChicagoDude
ChicagoDude

Reputation: 601

CURL php query formation - how to?

I am trying to form the following CURL post request through PHP? How do i do it, all of what i tried came back as invalid post parameters.

This is what i am trying to POST through php (i have the API_KEY, api_sig.. but dont know how put below post query through in PHP):

curl -d "api_key=KEY&sig=SIGNATURE&time_stamp=20&json=1" \ http://api.i.com/v1/update/

Upvotes: 1

Views: 2848

Answers (3)

user536677
user536677

Reputation: 1

Please refer to following PHP code

 define('POSTURL', 'http://api.iq.com/v1/update/');
 define('POSTVARS', 'api_key=API_KEY&api_sig=SIGNATURE&time_stamp=20090612111832&json=1');  //removed typo
 $ch = curl_init(POSTURL);
 curl_setopt($ch, CURLOPT_POST  ,1);
 curl_setopt($ch, CURLOPT_POSTFIELDS ,POSTVARS);
 curl_setopt($ch, CURLOPT_RETURNTRANSFER  ,1);  // RETURN THE CONTENTS OF THE CALL`
 $Rec_Data = curl_exec($ch);`
 curl_close($ch);

Upvotes: 0

subroutines
subroutines

Reputation: 1458

Put everything in one line:

curl -d "api_key=API_KEY&api_sig=SIGNATURE&time_stamp=20090612111832&json=1" http://api.iq.com/v1/update/

Use exec() to run it, for example

exec("curl -d \"api_key=API_KEY&api_sig=SIGNATURE&time_stamp=20090612111832&json=1\" http://api.iq.com/v1/update/", $results);

$results holds the returned data.

Upvotes: 0

useful
useful

Reputation: 472

This should work

$url = "http://api.iq.com/v1/update/";
$data = "api_key=API_KEY&api_sig=SIGNATURE&time_stamp=20090612111832&json=1";

$ch = curl_init($url);
curl_setopt($ch, CURLOPT_POST ,1);
curl_setopt($ch, CURLOPT_POSTFIELDS, $data);
curl_setopt($ch, CURLOPT_FOLLOWLOCATION, 1); /* obey redirects */
curl_setopt($ch, CURLOPT_HEADER, 0);  /* No HTTP headers */
curl_setopt($ch, CURLOPT_RETURNTRANSFER, 1);  /* return the data */

$result = curl_exec($ch);

curl_close($ch);

Upvotes: 5

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