CODEWITHSUNDEEP
jquerycss-selectorschildrenvisible
Glen
Glen

Reputation: 171

jquery selection of elements with no visible children

Here's my goal: do something on an element, an <optgrooup>, if all of its children are invisible.

My code below outlines the in red if it has any invisible children. But I want to do so only if all the children are invisible. If the element has any children that are visible, then don't highlight it.

How can I tweak the jQuery selector to do that?

Thanks in advance.

<select multiple="multiple" name="availableInstanceId" id="availableInstanceId">
<optgroup label="Option Group 1">
   <option >visible item 1</option>
   <option >visible item 2</option>
</optgroup>
<optgroup label="Option Group 2 - Should be highlighted">
   <option style="display:none;">invisible A</option>
   <option style="display: none">invisible B</option>
</optgroup>

<optgroup label="Option Group 3 - Should not be highlighted">
  <option >visible C</option>
  <option style="display: none">invisible D</option>
</optgroup></select>

<script type="text/javascript">
var filterOptions = function(e) {
  // Goal: highlight the <optgroup>'s that have *only* invisible children
  $( '#availableInstanceId > * > *:hidden').parent().css("border","3px solid red");
} 
$(document).ready(function() {
  filterOptions();
});
</script>

Screenshot of image here: http://img144.imageshack.us/img144/556/selectexample.gif

Upvotes: 8

Views: 9743

Answers (6)

Jed Schmidt
Jed Schmidt

Reputation: 2955

Assuming you want to exclude elements with no child elements:

 $(":has(*):not(:has(:visible))")

Working example.

UPDATE: This has much better performance than my original answer:

$(":hidden").parent().not( $(":visible").parent() )

Upvotes: 13

David Lefkon
David Lefkon

Reputation: 289

// answer to question changing css as desired

    if($.browser.msie || $.browser.safari){

        $('optgroup:not(:has(:hidden))').css("border","3px solid red");

    } else {

        $('optgroup:not(:has(:visible))').css("border","3px solid red");

    }

// remove empty optgroups example 

    if($.browser.msie || $.browser.safari){

        $('optgroup:not(:has(:hidden))').remove();

    } else {

        $('optgroup:not(:has(:visible))').remove();

    }

Upvotes: 1

brianpeiris
brianpeiris

Reputation: 10795

Credit goes to Jed Schmidt. The following code works in IE8.

Note that IE8 does not actually hide the <option> elements despite the display: none style. Also IE8 doesn't seem to accept border styles for <optgroup> elements.

Working sample: http://jsbin.com/aquya (Editable via http://jsbin.com/aquya/edit)

$(document).ready(function() {
  // Prevent CSS inherits
  $("option").css('backgroundColor', 'white')

  $("option")
    .filter(function(){
      return this.style.display == 'none';
    })
    .parent()
    .not($('option').filter(function(){
      return this.style.display != 'none';
    }).parent())
    .css('backgroundColor', 'blue')
    .css('border', '1px solid red'); //this doesn't work in IE8
});

Upvotes: 1

Jed Schmidt
Jed Schmidt

Reputation: 2955

This has much better performance than my original answer:

$(":hidden").parent().not( $(":visible").parent() )

Upvotes: 2

Samir Talwar
Samir Talwar

Reputation: 14330

How about two lines to do it? One to turn it on for every single element, and one to turn it off again for every one with a visible child?

$('#availableInstanceId > *').css("border","3px solid red");
$('#availableInstanceId > * > *:visible').parent().css("border","none");

Upvotes: 1

JP Silvashy
JP Silvashy

Reputation: 48525

You'll need to compare an array of all the :visible vs. :hidden

here is some pseudo code

if ($("#element:hidden").length == $("#element:visible").length) {
  // Do  stuff
} ...

Upvotes: 0

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