Reputation: 139
I'm working on a homework assignment for an image shrinking program in C++. My picture is represented by a 2D array of pixels; each pixel is an object with members "red", "green" and "blue." To solve the problem I am trying to access the 2D array one block at a time and then call a function which finds the average RGB value of each block and adds a new pixel to a smaller image array. The size of each block (or scale factor) is input by the user.
As an example, imagine a 100-item 2D array like myArray[10][10]. If the user input a shrink factor of 3, I would need to break out mini 2D arrays of size 3 by 3. I do not have to account for overflow, so in this example I can ignore the last row and the last column.
I have most of the program written, including the function to find the average color. I am confused about how to traverse the 2D array. I know how to cycle through a 2D array sequentially (one row at a time), but I'm not sure how to get little squares within an array.
Any help would be greatly appreciated!
Upvotes: 7
Views: 4083
Reputation: 53017
Something like this should work:
for(size_t bx = 0; bx < width; bx += block_width)
for(size_t by = 0; by < height; by += block_height) {
float sum = 0;
for(size_t x = 0; x < block_width; ++x)
for(size_t y = 0; y < block_height; ++y) {
sum += array[bx + x][by + y];
}
average = sum / (block_width * block_height);
new_array[bx][by] = average;
}
width
is the whole width, block_width
is the length of your blue squares on diagram
Upvotes: 4
Reputation: 33386
This is how you traverse an array in C++:
for(i=0; i < m; i++) {
for(j=0; j < n; j++) {
// do something with myArray[i][j] where i represents the row and j the column
}
}
I'll leave figuring out how to cylcle through the array in different ways as an exercise to the reader.
Upvotes: 3
Reputation: 3049
you could use two nested loops one for x and one for y and move the start point of those loops across the image. As this is homework I wont put any code up but you should be able to work it out.
Upvotes: 0