CODEWITHSUNDEEP
djangodjango-formsdjango-templates
tamakisquare
tamakisquare

Reputation: 17067

Django: How to access the display value of a ChoiceField in template given the actual value and the choices?

I have a ChoiceField in a bound form, whose choices are:

[('all', 'All users'), ('group', 'Selected groups'), ('none', 'None')]

In the template, I have no problem accessing its bound value (the actual value to be stored; the first element of each tuple) and the choices. With these pieces of info in hands, I know I should be able to access the display values, or the second element of each tuple. But how can I do that in the template? Thanks.

Upvotes: 15

Views: 20466

Answers (6)

JDavies
JDavies

Reputation: 2770

After not being able to use get_FOO_display due to using the 'union' method (As it returns a dictionary, not a list of objects). I wrote a quick template tag to convert the field display.

@register.simple_tag
def tag_get_display(obj):
    """
        Returns the display of the field when unable to access get_foo_display.

    """
    return CHOICES_LIST[obj][1]

Upvotes: -1

NMC
NMC

Reputation: 1326

If you use {{ form.instance.field }} in the form template, it should display the selected choice display name

Upvotes: -1

Thibault J
Thibault J

Reputation: 4446

Use the get_FOO_display property.

** Edit **

Oups! Quick editing this answer, after reading the comments below.

bound_form['field'].value()

Should work according to this changeset

Upvotes: 5

Nick
Nick

Reputation: 8309

I have a contact form using the FormView class-based view. The contact form has some ChoiceField fields. I'm not storing the submissions in the database; just emailing them to the site owner. This is what I ended up doing:

def form_valid(self, form):
    for field in form.fields:
        if hasattr(form[field].field, 'choices'):
            form.cleaned_data[field + '_value'] = dict(form[field].field.choices)[form.cleaned_data[field]]

    ...

Upvotes: 0

bmihelac
bmihelac

Reputation: 6323

I doubt that it can be done without custom template tag or filter. Custom template filter could look:

@register.filter
def selected_choice(form, field_name):
    return dict(form.fields[field_name].choices)[form.data[field_name]]

Upvotes: 13

Kumar
Kumar

Reputation: 417

Check this link - https://docs.djangoproject.com/en/dev/ref/models/instances/#django.db.models.Model.get_FOO_display

You can use this function which will return the display name - ObjectName.get_FieldName_display()

Replace ObjectName with your class name and FieldName with the field of which you need to fetch the display name of.

Upvotes: 0

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