CODEWITHSUNDEEP
xmlxsdxmllint
Dave Jarvis
Dave Jarvis

Reputation: 31171

No matching global declaration available for the validation root

Background

Validate an XML document using a schema.

Problem

The simplest form of the problem is shown in two files.

XML Document file.xml

<?xml version="1.0"?>
<recipe xmlns:r="http://www.namespace.org/recipe">
  <r:description>
    <r:title>sugar cookies</r:title>
  </r:description>
</recipe>

XSD Document schema.xsd

<?xml version="1.0" encoding="utf-8"?>
<xsd:schema
   version="1.0"
   xmlns:xsd="http://www.w3.org/2001/XMLSchema"
   xmlns:r="http://www.namespace.org/recipe">

  <xsd:complexType name="recipe">
    <xsd:choice>
      <xsd:element name="description" type="descriptionType"
        minOccurs="1" maxOccurs="1" />
    </xsd:choice>
  </xsd:complexType>

  <xsd:complexType name="descriptionType">
    <xsd:all>
      <xsd:element name="title">
        <xsd:simpleType>
          <xsd:restriction base="xsd:string">
            <xsd:minLength value="5" />
            <xsd:maxLength value="55" />
          </xsd:restriction>
        </xsd:simpleType>
      </xsd:element>
    </xsd:all>
  </xsd:complexType>
</xsd:schema>

Error

The full error message from xmllint:

$ xmllint --noout --schema schema.xsd file.xml

file.xml:2: element recipe: Schemas validity error : Element 'recipe': No matching global declaration available for the validation root. file.xml fails to validate

Question

What is the correct syntax (or what schema attributes are missing) to ensure that the given schema can be used to successfully validate the given XML document?

Upvotes: 62

Views: 117741

Answers (3)

Aravind Yarram
Aravind Yarram

Reputation: 80186

Make recipe global

Only global element definitions can be used as root elements. Your schema only has complex types and hence the error.

Change the <xsd:complexType name="recipe"> to <xsd:element name="recipe"><xsd:complexType>:

Schema file: recipe-now-global.xsd

<?xml version="1.0" encoding="utf-8"?>
<xsd:schema
   version="1.0"
   xmlns:xsd="http://www.w3.org/2001/XMLSchema"
   xmlns:r="http://www.namespace.org/recipe">

  <xsd:element name="recipe">
    <xsd:complexType>
      <xsd:choice>
        <xsd:element name="description" type="descriptionType"
          minOccurs="1" maxOccurs="1" />
      </xsd:choice>
    </xsd:complexType>
  </xsd:element>

  <xsd:complexType name="descriptionType">
    <xsd:all>
      <xsd:element name="title">
        <xsd:simpleType>
          <xsd:restriction base="xsd:string">
            <xsd:minLength value="5" />
            <xsd:maxLength value="55" />
          </xsd:restriction>
        </xsd:simpleType>
      </xsd:element>
    </xsd:all>
  </xsd:complexType>
</xsd:schema>

Read more about this here

NOTE: This still won't validate, because you have an unreleated namespace error...

$ cat file.xml | xmllint --noout --schema recipe-now-global.xsd -
-:3: element description: Schemas validity error : Element '{http://www.namespace.org/recipe}description': This element is not expected. Expected is ( description ).
- fails to validate

...but it WILL validate if you ignore that namespace error quick-and-dirty like:

$ cat file.xml | sed 's/r://g' | xmllint --noout --schema recipe-now-global.xsd -
- validates

See tom redfern's answer for details on that namespace problem.

Upvotes: 21

tom redfern
tom redfern

Reputation: 31760

You need to change your XML instance. Your current one says that there is a type called description in the namespace http://www.namespace.org/recipe. However, in your XSD definition, the only types exposed in that namespace are called recipe and descriptionType.

So either define a type called description in the XSD schema, or change your instance so you are referencing the recipe type correctly:

File ns-changed.xml:

<?xml version="1.0"?>
<r:recipe xmlns:r="http://www.namespace.org/recipe">
  <description>
    <title>sugar cookies</title>
  </description>
</r:recipe>

UPDATE This is only half the solution - the other half is in @Aravind's answer here: https://stackoverflow.com/a/8426185/569662

Upvotes: 32

Klesun
Klesun

Reputation: 13673

In my practice, I got the No matching global declaration available for the validation root in two cases:

  • If XSD does not contain an <xsd:element name="recipe" .../> explained in @aravind-r-yarram's answer.

  • If <recipe/> in XML does not contain an xmlns attribute. In such case adding the xmlns will help:

      <recipe xmlns="http://www.namespace.org/recipe">
      ...
  </recipe>

Upvotes: 12

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