Reputation: 39
Hi I'm new to XSLT and I'm trying to display the value of a parent node along with the values of my data.
I have this XML..
<?xml-stylesheet type="text/xsl" href="Sample.xsl"?>
<DataView Client="Client1" ID="1000" TimeStamp="12/7/2011 5:35:09 PM">
<Group ID="5000" Name="GroupName1">
<SubGroup ID="7000" Order="0" Name="NameIWant1">
<Data ID="1" Name="DataName1" Order="0">1</Data>
<Data ID="2" Name="DataName2" Order="0">2</Data>
<Data ID="3" Name="DataName3" Order="0">3</Data>
<Data ID="12" Name="DataName4" Order="0">4</Data>
</SubGroup>
<SubGroup ID="8000" Order="0" Name="NameIWant2">
<Data ID="1" Name="DataName1" Order="0">6</Data>
<Data ID="2" Name="DataName2" Order="0">7</Data>
<Data ID="3" Name="DataName3" Order="0">8</Data>
<Data ID="12" Name="DataName4" Order="0">9</Data>
</SubGroup>
</Group>
</DataView>
Ive written the basic XSL to walk the values
<?xml version="1.0" encoding="ISO-8859-1"?>
<xsl:stylesheet version="1.0" xmlns:xsl="http://www.w3.org/1999/XSL/Transform">
<xsl:template match="/">
<html>
<body>
<h2>My Data</h2>
<table border="1">
<tr bgcolor="#9acd32">
<th>DataName1</th>
<th>DataName2</th>
<th>DataName3</th>
<th>DataName4</th>
</tr>
<xsl:for-each select="DataView/Group/SubGroup">
<tr>
<xsl:for-each select="Data">
<td><xsl:value-of select="."/></td>
</xsl:for-each>
</tr>
</xsl:for-each>
</table>
</body>
</html>
</xsl:template>
</xsl:stylesheet>
How do I retrieve and display the attribute value of Subgroup "Name" so my table looks like this...
MyData
NameIWant1 1 2 3 4
NameIWant2 6 7 8 9
Any help is very much appreciated!!
Upvotes: 2
Views: 436
Reputation: 60414
The simple, short answer is to add the following just before the inner for-each
loop:
<td><xsl:value-of select="@Name"/></td>
You're already in the context of a DataView/Group/SubGroup
node, so you just need to use the attribute axis specifier (@
) to select one of its attributes by name.
However, (as usual) I think this is better expressed using individual templates. The for-each
loop is almost never necessary in XSLT. The following stylesheet produces the desired result:
<xsl:stylesheet version="1.0" xmlns:xsl="http://www.w3.org/1999/XSL/Transform">
<xsl:output method="xml" indent="yes" omit-xml-declaration="yes"/>
<xsl:strip-space elements="*"/>
<xsl:template match="/">
<html>
<body>
<h2>My Data</h2>
<table border="1">
<tr bgcolor="#9acd32">
<th>Subgroup</th>
<th>DataName1</th>
<th>DataName2</th>
<th>DataName3</th>
<th>DataName4</th>
</tr>
<xsl:apply-templates/>
</table>
</body>
</html>
</xsl:template>
<xsl:template match="SubGroup">
<tr>
<td><xsl:value-of select="@Name"/></td>
<xsl:apply-templates/>
</tr>
</xsl:template>
<xsl:template match="Data">
<td><xsl:apply-templates/></td>
</xsl:template>
</xsl:stylesheet>
Output:
<html>
<body>
<h2>My Data</h2>
<table border="1">
<tr bgcolor="#9acd32">
<th>Subgroup</th>
<th>DataName1</th>
<th>DataName2</th>
<th>DataName3</th>
<th>DataName4</th>
</tr>
<tr>
<td>NameIWant1</td>
<td>1</td>
<td>2</td>
<td>3</td>
<td>4</td>
</tr>
<tr>
<td>NameIWant2</td>
<td>6</td>
<td>7</td>
<td>8</td>
<td>9</td>
</tr>
</table>
</body>
</html>
Upvotes: 1
Reputation: 167516
<table border="1">
<thead>
<tr bgcolor="#9acd32">
<th>SubGroupName</th>
<th>DataName1</th>
<th>DataName2</th>
<th>DataName3</th>
<th>DataName4</th>
</tr>
</thead>
<tbody>
<xsl:for-each select="DataView/Group/SubGroup">
<tr>
<td>
<xsl:value-of select="@Name"/>
</td>
<xsl:for-each select="Data">
<td><xsl:value-of select="."/></td>
</xsl:for-each>
</tr>
</xsl:for-each>
</tbody>
</table>
Upvotes: 0