CODEWITHSUNDEEP
powershell
bbinnebose
bbinnebose

Reputation: 45

Powershell new-item directory with a parameter as part of folder name

I'd like to create a folder based on a parameter used in the name, so for example:

    $Website = "test"
    new-item \\172.1.1.1\C`$\Folder\$Website_Archive -type directory

The _Archive needs to be part of the folder name but I cannot figure out how to pass the $Website with the _Archive included.

Here is the error I get:

New-Item : Item with specified name \172.1.1.1\C$\Folder\ already exists. At line:2 char:9 + new-item <<<< \172.1.1.1\C`$\Folder\$Website_Archive -type directory + CategoryInfo : ResourceExists: (\172.1.1.1\C\Folder\:String) [New-Item], IOException + FullyQualifiedErrorId : DirectoryExist,Microsoft.PowerShell.Commands.NewItemCommand

If I remove the '_Archive' from the line it will create the folder named "test". I'm assuming it's looking for a parameter of $Website_Archive and not finding it so it tries to just recreate the root folder. How can I get the parameter passed into the folder name?

Thanks!

BB

Upvotes: 1

Views: 16126

Answers (3)

manojlds
manojlds

Reputation: 301587

Apart from what @JohnL mentions, I prefer string formatting, especially when many variables are involved:

"\\172.1.1.1\C`$\Folder\{0}_Archive" -f $Website

Upvotes: 4

JohnL
JohnL

Reputation: 4002

Either escape as per JNK's answer, enclose $Website with $(...)

new-item "\\17.1.1.1\C`$\Folder\$($Website)_Archive" -type directory

Upvotes: 3

JNK
JNK

Reputation: 65217

Just escape the underscore with a backtick 

new-item "\\17.1.1.1\C`$\Folder\$Website`_Archive" -type directory

Upvotes: 4

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