Reputation: 6762
I have one temporary table that contains userID
and taskID
. It is called CompletedTasks
.
I have a second table that contains userID
and taskID
. It is called PlannedTasks
.
I need to get a list of all taskID
s that were completed, but not planned.
So, I need to somehow weed out from completed tasks, all rows where both:
PlannedTasks.userID != CompletedTasks.userID
AND
PlannedTasks.taskID != CompletedTasks.taskID
Upvotes: 42
Views: 40403
Reputation: 1
the first answer pretty good, It did work for me, just was missing a ")" after PlannedTasks. I need to weed out the elements from one table, that were in the other, so...
SELECT *
FROM CompletedTasks
WHERE (userID, taskID) NOT IN
( SELECT userID, taskID
FROM PlannedTasks )
) ;
This is my code:
$query_C_Ranking = sprintf("SELECT *
FROM tblpinturas
WHERE (idCode) NOT IN
(SELECT idCode FROM tblranking)
");
Upvotes: 0
Reputation: 319
@ypercubeᵀᴹ Thanks for sharing below mention query
SELECT * FROM CompletedTasks WHERE (userID, taskID) NOT IN
( SELECT userID, taskID FROM PlannedTasks) ;'
My problem solved.
Upvotes: 1
Reputation: 115650
You can use this (more compact syntax):
SELECT *
FROM CompletedTasks
WHERE (userID, taskID) NOT IN
( SELECT userID, taskID
FROM PlannedTasks
) ;
or the NOT EXISTS
version (which although more complex, should be more efficient with proper indexes):
SELECT c.*
FROM CompletedTasks AS c
WHERE NOT EXISTS
( SELECT 1
FROM PlannedTasks AS p
WHERE p.userID = c.userID
AND p.taskID = c.taskID
) ;
and of course the LEFT JOIN / IS NULL
version that @jmacinnes has in his answer.
Upvotes: 98
Reputation: 1609
Is this what you need?
select ct.* from
completedTasks ct
left outer join plannedTasks pt on ct.taskId = pt.TaskId and ct.userId = pt.userId
where pt.taskId is null
However, I agree with the comment - given what we know from the question a status column sounds like a better schema than two tables.
Upvotes: 5